3 years ago

In a geometry class, the students were asked to prove the theorem below by contradiction.

1 answer:

4 0

<span>The contradiction term for "at most one obtuse angle" is "no obtuse angles
so therefore i conclude that the </span> statement she will most likely use as an assumption is
Let each angle of a triangle be acute
so option A is correct
hope it helps

You might be interested in

Janae and Jerome each have m marbles. Gwen has 4(m + 2) marbles. John has 8m + 4 marbles. If John has more marbles than Janae, J

Ne4ueva [31]

Answer:

C, D, E

Step-by-step explanation:

The numbers of marbles are:

Janae - m;
Jerome - m;
Gwen - 4(m+2);
John - 8m+4.

Janae, Jerome, and Gwen combined have

m + m + 4(m+2) = m + m +4m + 8 =6m + 8 marbles.

If John has more marbles than Janae, Jerome, and Gwen combined, then

$8m+4>6m+8,\\ \\8m-6m>8-4,\\ \\2m>4,\\ \\m>2.$

So, possible answers are

Janae and Jerome each have 3 marbles;
Janae and Jerome each have 4 marbles;
Janae and Jerome each have 5 marbles.

7 0

3 years ago

7 and2/3 - 5and 5/8=

dolphi86 [110]

7 2/3 - 5 5/8 = 7 16/24 - 5 15/24 = 2 1/24

4 0

3 years ago

The graph shows two lines, A and B. A graph is shown with x- and y-axes labeled from 0 to 6 at increments of 1. A straight line

mixas84 [53]

( Part A: Ok 2,6 and 6,2 and 0,3 and 4.5,6 you can add 2,6 and every other number with part b which is 2,6 +0,3= 2,3 and also 2,6+4.5,6= 6.5,12 and you can do the same with 6,2 and you will get 6,5 and 10.5,8)
(Part B: 2,3^6.5,12^6,5^10.5,8)
~Riley Hope this helped :P

7 0

3 years ago

J u l i a n has partially filled the p r i s m below with 16 unit cubes. How many more unit cubes will he need to completely fil

Wittaler [7]

add it

Step-by-step explanation:

11+20+25+36

8 0

2 years ago

List the sides of △ABC in order from longest to shortest if the angles of △ABC have the following measures: m∠W = 4x - 1, m∠X =

Leto [7]

Answer:

w=4x

Step-by-step explanation:

5 0

3 years ago