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Blizzard [7]
3 years ago
8

Can you help me? Please show how you work it out

Mathematics
1 answer:
qaws [65]3 years ago
8 0

Swimmers: 50 children ÷ 12 = 4.2  (you can't have a decimal so you must round up)

5 adults are need.

Dancers: 32 children ÷ 15 = 2.1  (you can't have a decimal so you must round up)

3 adults are need.

Minimum number of adults needed is: 5 for swimmers + 3 for dancers = 8 adults

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Last one, ​please :)
KengaRu [80]

Answer:

m∠X = 29°

m∠V = 61°

m∠W == 90°⇒given

Step-by-step explanation:

∵ ΔXWV is right angle at W

∴ m∠W = 90°

∴ m∠X + m∠V = 180° - 90° = 90°

∵ m∠X = 2x + 5 and m∠V = 4x +13

∴ 2x + 5 +4x + 13 = 90

∴ 6x + 18 = 90

∴ 6x = 90 - 18 =72

∴ x = 72/6 = 12

∴ m∠X = 2(12) + 5 = 29°

∴ m∠V = 4(12) + 13 = 61°

5 0
2 years ago
Which expression could represent the length of a rectangle that has an area equal to 4x2+12x?
grandymaker [24]

there are two expressions that can represent the length of the rectangle, these two expressions are:

L = x

or

L = (4x + 12)

<h3>Which expression could represent the length of the rectangle?</h3>

Remember that for a rectangle of length L and width W, the area is given by:

A = L*W

In this case, we know that the area is:

A = 4x^2 + 12x

We can factorize that expression into:

A = x*(4x + 12)

So there are two expressions that can represent the length of the rectangle, these two expressions are:

L = x

or

L = (4x + 12)

If you want to learn more about rectangles:

brainly.com/question/17297081

#SPJ1

6 0
8 months ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
2 years ago
Put these decimals in order starting with the smallest.
iVinArrow [24]

Answer:

8.008

8.018

8.088

8.808

8.88

<em><u>If this helped, please consider picking this answer as the Brainliest Answer. Thank you!</u></em>

3 0
2 years ago
Read 2 more answers
(PLZ HELP ME)
Mumz [18]

Answer:

d 32 ft

Step-by-step explanation:

multiply 8 and 4


5 0
3 years ago
Read 2 more answers
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