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sergiy2304 [10]
3 years ago
9

12ad^3 and which terms are like terms?

Mathematics
1 answer:
Marat540 [252]3 years ago
4 0

Answer: Like terms are terms with the exact same variables, and the exact same degree of each variable...simply put, the exponents of each variable have to be exactly the same. The given term 12 ad³ has variables a and d. a has a degree of 1 and d has a degree of 3.

Step-by-step explanation:

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Answer please!! urgent!!
Talja [164]

Answer:

a

Step-by-step explanation:

4 0
3 years ago
ILL GIVE BRAINLIEST IF CORRECT!! The average of x+6, 6x+2, and 2x+7 is 4x-7. What is x?
mina [271]

Answer:

35/3

Step-by-step explanation:

\frac{x+6 + 6x+2+x+6}{3} =4x-7

Simplify to get

9x+14=3(4x-7)

35=3x

x=35/3 or 11.66

6 0
3 years ago
What is the median of the data set? <br> {10, 15, 14, 14, 10, 10, 8, 18, 11, 12, 17, 16}
Alexus [3.1K]
The median of a data set is the 'middle number'. You can find the median by listing the given numbers from least to greatest (left to right) and finding the middle number.

8, 10, 10, 10, 11, 12, 14, 14, 15, 16, 17, 18

Cross one out on each side before getting to your last number that should be in the middle. 

The middle numbers are: 12 and 14. If it was only one number, we could already have the answer, but since it is two numbers in the middle, we need to add them up and divide by 2. 

12 + 14 = 26
26 ÷ 2 = 13

So, the median of the data set is: 13.
6 0
3 years ago
I need help plz someone help me solved this problem I need help ASAP! I will mark you as brainiest!
valina [46]

Answer: k = 12

<u>Step-by-step explanation:</u>

x² + kx + 36 = 0

In order for x to have exactly one solution, it must be a perfect square.

(x + √36)² = 0

(x + 6)² = 0

(x + 6)(x + 6) = 0

x² + 6x + 6x + 36 = 0

x² + 12x + 36 = 0

 k = 12

8 0
3 years ago
The Circle with a center (10,1) and the radius 5 has equation
liberstina [14]
<h3>Answer:  (x-10)^2 + (y-1)^2 = 25</h3>

============================================

Explanation:

The general template of a circle is

(x-h)^2 + (y-k)^2 = r^2

Where,

  • (h,k) is the center
  • r is the radius

We are given (10,1) as the center so (h,k) = (10,1) meaning that h = 10 and k = 1 pair up together.

r = 5 is the given radius.

-----

Plug the values h = 10, k = 1, r = 5 into the equation to get:

(x-h)^2 + (y-k)^2 = r^2

(x-10)^2 + (y-1)^2 = 5^2

(x-10)^2 + (y-1)^2 = 25

5 0
3 years ago
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