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3 years ago

7

A container holds 8 quarts of juice. How much is this in gallons? Use the table below. Include the correct unit in your answer.

Unit Symbol Fact Volume fluid ounce floz cup c 1c = 8floz pint pt 1pt = 2c quart qt 1qt = 2pt gallon gal 1gal = 4qt

2 answers:

morpeh [17]3 years ago

6 0

4 maybe i am bad at math soi could be wrong

Margaret [11]3 years ago

3 0

Since there are 4 quarts in a gallon, 8 quarts equals 2 gallons

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The difference of a number and fifteen is two. Write and Algebra Sentence then solve the number.

damaskus [11]

Answer:

<h2><u><em>x - 15 = 2</em></u></h2>

Step-by-step explanation:

The difference of a number and fifteen is two. Write and Algebra Sentence then solve the number.

x - 15 = 2

x = 2 + 15

x = 17

-------------------------

check

17 - 15 = 2

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<u>the answer is good</u>

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melisa1 [442]

144+64= 178

$\sqrt{178 } = 13.3$

a^2+b^2= c^2

Whenever finding a missing length use the formula up above :

a^2+b^2= c^2

a^2-b^2= c^2

144-64= 80

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3 years ago

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svetoff [14.1K]

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3 years ago

Solve for x.<br><br> <img src="https://tex.z-dn.net/?f=15log_%7B8%7D%20%28-2x-7%29-2%3D3" id="TexFormula1" title="15log_{8} (-2x

vova2212 [387]

Answer: $x=-4.5$

Step-by-step explanation:

Add 2 to both sides of the equation and divide both sides of the equation by 15. Then:

$15log_{8} (-2x-7)-2+2=3+2\\15log_{8} (-2x-7)=5\\\\\frac{15log_{8} (-2x-7)}{15}=\frac{5}{15}\\\\log_{8}(-2x-7)=\frac{1}{3}$

Apply base 8 to both sides of the equation:

$8^{log_{8}(-2x-7)}=8^{\frac{1}{3}}\\\\-2x-7=8^{\frac{1}{3}}$

Solve for "x", then you get:

$-2x-7=8^{\frac{1}{3}}\\\\-2x=\sqrt[3]{8}+7\\\\ x=\frac{\sqrt[3]{8}+7}{-2}\\\\x=-4.5$

5 0

3 years ago