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MissTica
3 years ago
10

Find the area of this shape.

Mathematics
1 answer:
mart [117]3 years ago
5 0

Answer:

shape AREA= 35cm^2

Step-by-step explanation:

you should know that this shape is a combination of triangle and trapezoid. therefore you have to find the area of each shape and add them.

A=h/2(b1 + b2) for trapezoid

A=2/2((4+4)+4)

A=1*12

A=12cm^2

A=bh/2. for TRIANGLE

A=1/2((4+4)*5.75)

A=1/2(46)

A=23cm^2

shape AREA= triangle AREA + trapezoid AREA

shape AREA=12cm^2 + 23cm^2

shape AREA= 35cm^2

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PLEASE CHECK MY ANSWERS (PART 2)
Anna007 [38]
3 is incorrect, should be 28.9

16^2 + 18^2 = EG^2
256 + 324
580 = EG^2
EG ≈ 24.08

16^2 + 24.08^2 = AG^2
256 + 580 = AG^2
836 = AG^2
AG ≈ 28.9

5 is incorrect:

The base is 8.
Draw an altitude the base.
Since the triangle is isoceles, it divides the base in half.
Half of that base is 4.
Two right triangles have been formed with one leg 4 and hypotenuse 8.
4^2 + b^2 = 8^2
16 + b^2 = 64
b^2 = 48
b ≈ 6.93

The height of the triangle is 6.93, the base is 8.
A = bh/2 = 8*6.93/2 ≈ 27.7 ≈ 28



3 0
4 years ago
The table below shows an inequality and a number by which to divide both sides.
IRISSAK [1]

Answer:

i dont see a table

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The temperature is currently 60 F. If the temperature drops on average 2 degrees per day, how many days will it be until the tem
Bezzdna [24]
9 days

because legit 60 - 42 = 18
18 divide 2 = 9 days

Or you could’ve just done 42 + 2 +2+2 until you get to 60 and you would do it 9 times. Meaning 9 days
8 0
2 years ago
I marked all 3 parts. I need to know part C (the shaded part). anybody mind helping?​
Mnenie [13.5K]

Answer:

Area of shaded part ABCEF = 66 sq.cm

Step-by-step explanation:

AB = 8cm

CD = 8cm

Let DE = x cm

CE = 3x cm

CD =  CE + DE = 8cm

        x + 3x = 8

4x = 8

x = 8/4 = 2 cm

DE = 2cm

CE = 3 * 2 = 6 cm

Area of triangle ADE = 1/2 * base * height

                                   = 1/2 * DE * AD

                                    = 1/2 * 2 * 11 = 11 sq. cm

Area of triangle AEF = Area of triangle ADE = 11 sq. cm

Area of Rectangle ABCD =  l * b = 8 * 11 = 88 sq.cm

Area of shaded part ABCEF =  Area of Rectangle ABCD - (Area of triangle AEF + Area of triangle ADE)

    = 88 - ( 11 + 11 )  = 88 -22 = 66 sq.cm

6 0
3 years ago
16. Solve for the angle x.<br> cos(¹/2x) = ¹/2
Basile [38]

Answer:

We know that ,

\rightarrow \tt \cos( \frac{\pi}{3} )  =  \frac{1}{2}

So ,

\:  \rightarrow \tt \cos( \frac{1}{2}x )    =  \cos( \frac{\pi}{3} )  \\  \\   \rightarrow \tt \frac{1}{2}.x =  \frac{\pi}{3}  \\  \\ \rightarrow \tt x =  \frac{2\pi}{3}

we can add 2 pi to it since there will be no change in the value

Also,

\: \rightarrow \tt  \cos( \frac{14\pi}{6} )  =  \frac{1}{2}  \\  \\  \\ \rightarrow \tt \frac{1}{2}  x =  \frac{14\pi}{6}  \\  \\ \rightarrow \tt x =  \frac{7\pi}{3}

Answer : Option B

6 0
2 years ago
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