Solve for the variable in the following proportion. 36/y = 1.2/2 y=

WILL GIVE BRAINLIEST!!!!!! 50 PTS!!!!!!!!

Softa [21]

Let the original price be p.

Then the sale price was (1.00-0.18)p, or 0.82p.

Emerson must pay tax on this sale price. It is 0.08(0.82p) = 0.0656p.

Thus, the final cost of the game was 0.82p + 0.0656p = 0.886p.

4 0

4 years ago

8-4d=12 what is d equal to ?

NARA [144]

Answer:d=-1

Step-by-step explanation: you subtract 8 from both sides to get -4d=4 then divide -4 to get d alone. Which will get you to -1=d

4 0

3 years ago

Quadrilateral ABCD is translated to get quadrilateral A’B’C’D’. Vertex A is at (-5, 2), and vertex A’ is at (2, -2). Quadrilater

Rudik [331]

Answer:

vertex B' is at (1, 1)

Step-by-step explanation:

Let us revise the rules of translation of a point

If the point (x, y) translated horizontally to the right by h units then its image is (x + h, y) ⇒ T (x, y) → (x + h, y)

If the point (x, y) translated horizontally to the left by h units then its image is (x - h, y) ⇒ T (x, y) → (x - h, y)

If the point (x, y) translated vertically up by k units then its image is (x, y + k)→ (x + h, y) ⇒ T (x, y) → (x, y + k)

If the point (x, y) translated vertically down by k units then its image is (x, y - k) ⇒ T (x, y) → (x, y - k)

Let us use the rules to solve our question

∵ Vertex A = (-5, 2)

∵ Vertex A' = (2, -2)

→ The coordinates of the two points changed which means the

quadrilateral is translated horizontally and vertically

∵ The x-coordinate of A = -5

∵ The x-coordinate of A' = 2

→ Which means it moves to the right, so use the first rule above

∴ the rule of translation is T (x, y) → (x + h, y)

∴ x → x + h

∵ x = -5 and x + h = 2

∴ -5 + h = 2

→ Add 5 to both sides

∴ -5 + 5 + h = 2 + 5

∴ h = 7

∴ The quadrilateral is translated 7 units right

∵ The y-coordinate of A = 2

∵ The y-coordinate of A' = -2

→ Which means it moves down, so use the 4th rule above

∴ the rule of translation is T (x, y) → (x, y - k)

∴ y → y - k

∵ y = 2 and y - k = -2

∴ 2 - k = -2

→ Add K to both sides

∴ 2 - k + k = -2 + k

∴ 2 = -2 + k

→ Add 2 to both sides

∴ 2 + 2 = -2 + 2 + k

∴ 4 = k

∴ The quadrilateral is translated 4 units down

→ Let us find B'

∵ T (x, y) → (x + h, y - k) is the rule of translation

∵ B = (-6, 5)

∵ h = 7 and k = 4

∴ B' = (-6 + 7, 5 - 4)

∴ B' = (1, 1)

∴ vertex B' is at (1, 1)

6 0

4 years ago

I need hellllllllllllllppppp

Gennadij [26K]

The answer is d i think

4 0

3 years ago

You and your friend race on a trail that is 10 miles long. In each situation, does your friend pass you before the end of the tr

Sliva [168]

For the first example given the answer would be No. you have a 4 mile head start. at the 4 mile line, your friend starts at 8 miles an hour and you start running at 6 miles an hour. basic addition should give the answer. In one hour time, you wouldve ran 6 miles plus the 4 you had as a head start, giving you the 10 miles you needed to reach the finish line. He on the other hand, Biked 8 miles in an hour time. By that time, you had just reached the finish line.

So the answer is no for the first example

For the second example the maths get bit harder. You start at the 5 mile point and you friend starts at the beginning point. You only need 5 miles to win, and your friend needs double (its actually more than double, because if it was perfectly doubled, you would tie the race. Your pace just has to be a bit more than half of his speed. his speed is 17mph. yours, by logic, needs to be even a tad bit more than 8.5mph. You need to have a faster speed than 8.5mph (8.51mph works perfectly) and you win by a hair. But when we se your example, you're only going at 7mph. A whole mile and a half behind pace. Sadly, he passes you short before winning.

The second example is YES he does pass you before the end of the trail.

Hope this helped. I spent around 20 minutes writing this answer, and a 5 star, like and noter as the "BRAINLIEST ANSWER" would be very much apreciated! Have a good day!!

7 0

4 years ago