<u>Answer</u>
Incorrect
<u>Explanation</u>
Unpack the problem:
Let the distance round the track to be X.
Speed is the ratio of distance to time.
Robert run a distance of (1/2)x
Elaine run a distance of (3/4)x
Make a plan:
Finding the speed of each.
Compare their speeds to determine who ran faster than who.
Solution:
Robert's speed =(1/2)x/(5/6)
=1/2×6/5x
= (3/5)x
= 0.6x
Elaine's speed = (3/4)x/(9/10)
= (3/4)×(10/9)x
= (5/6)x
= 0.83333x
<em>Elaine ran faster than Robert. </em>
<u>Look back and explain:</u>
0.83333x > 0.6x
Elaine's speed is higher than Robert's speed.
This shows that Elaine ran faster than Robert.
Answer:
The minimum sample size required is 207.
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population mean <em>μ</em> is:
The margin of error of this confidence interval is:
Given:
*Use a <em>z</em>-table for the critical value.
Compute the value of <em>n</em> as follows:
![MOE=z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\\3=2.576\times \frac{29}{\sqrt{n}} \\n=[\frac{2.576\times29}{3} ]^{2}\\=206.69\\\approx207](https://tex.z-dn.net/?f=MOE%3Dz_%7B%5Calpha%20%2F2%7D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%5C%5C3%3D2.576%5Ctimes%20%5Cfrac%7B29%7D%7B%5Csqrt%7Bn%7D%7D%20%5C%5Cn%3D%5B%5Cfrac%7B2.576%5Ctimes29%7D%7B3%7D%20%5D%5E%7B2%7D%5C%5C%3D206.69%5C%5C%5Capprox207)
Thus, the minimum sample size required is 207.
-3x + 10 = 34
Subtract 10 from both sides:
-3x = 24
Divide both sides by -3:
X = 24 / -3
X = -8
musiclover10045
Middle School Mathematics 39+20 pts
I have two questions to solve
-3x+10=34
13x-4=11x+10-8
Combine like terms on the right side:
13x -4 = 11x + 2
Subtract 11x from both sides:
2x -4 = 2
Add 4 to both sides:
2x = 6
Divide both sides by 2:
X = 6/2
X = 3
Yes, to make it simpler and easier to tell, you could put both these fractions into decimals or percentages.
4/6 as a decimal would be .66 or 66%
4/7 as a decimal would be .57 or 57%
Hope this helps! :}
Uh sure if you give me the problem I could help
