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iris [78.8K]
3 years ago
7

What is 22/7 out to 4 places? What is pi

Mathematics
1 answer:
marysya [2.9K]3 years ago
7 0

Answer:

22/7 is 3.1428

Pi is 3.1415

Difference is 0.0012

Step-by-step explanation:Divide 22 by 7 to get the first part. Look up or enter pie on your calculator. Subtract pi from 22/7.

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Solve the equation 40 = -10(y+0.3). what does the y equal​
alexdok [17]

Answer:

y = -4.3

Step-by-step explanation:

40 = -10(y + 0.3) <em>{Step 1: Use the distributive property to multiply -10 by y + 0.3}</em>

40 = -10y + -10(0.3)

40 = -10y - 3 <em>{Step 2: Add 3 to both sides.}</em>

40 + 3 = -10y

43 = -10y <em>{Step 3: Divide both sides by -10}</em>

43/-10 = y

-4.3 = y

y equals -4.3.

4 0
3 years ago
Read 2 more answers
Answer number 2 pleaseeee thank you
Fittoniya [83]

Hi!

a: <em>F </em><em>n </em><em>G </em>=(Intersection) {4,6,8,10}

b: <em>F </em><em>n </em><em>H </em>={empty set}

Because there is no common element between the elements of set F and the elements of set H.

Note: It may not be very clear as I don't speak English.

God work!

4 0
1 year ago
Multiply. Enter the product in singlets form. 10/18x9/10=
Alexeev081 [22]

Answer:

1/2

Step-by-step explanation:

6 0
2 years ago
Divide. Reduce the answer to lowest terms.<br><br> 1/5 ÷ 3/4
Nostrana [21]

Answer:

4/15

Step-by-step explanation:

  1. 1/5÷3/4 is the same as 1/5•4/3 by using same, change, reciprocal.
  2. 1/5•4/3=4/15.
  3. 4/15 cannot be simplified any more so the answer is 4/15.
6 0
3 years ago
Read 2 more answers
The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal with a mean of 16.12 OZ and a
elena-14-01-66 [18.8K]

Answer: 90.82%

Step-by-step explanation:

Given : The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal .

Mean : \mu=16.12\text{ OZ}

Standard deviation: \sigma=0.09\text{ OZ}

Let X be the random variable that represents the amount of soda in bottles.

Formula for z-score : z=\dfrac{x-\mu}{\sigma}

Z-score for 16 oz: z=\dfrac{16-16.12}{0.09}=-1.33

Using the standard normal z-distribution table , the probability that the soda bottles that contain more than the 16 OZ is given by :_

P(x>60)=P(z>-1.33)=1-P(x\leq-1.33)=1-0.0917591=0.9082409\approx0.9082\approx90.82\%

Hence, the percentage of the soda bottles that contain more than the 16 OZ advertised is 90.82% .

8 0
3 years ago
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