<span>Solving the equation for Y = 1.
5 * (3 * 1 - 2) = 15 * 1 - 10
5 * (3 - 2) = 15 -10
5 * 1 = 5
5 = 5
Solving the equation for Y = 2.
5 * (3 * 2 - 2) = 15 * 2 - 10
5 * (6 - 2) = 30 -10
5 * 4 = 20
20 = 20
Solving the equation for Y = 4.
5 * (3 * 4 - 2) = 15 * 4 - 10
5 * (12 - 2) = 60 -10
5 * 10 = 50
50 = 50
Solving the equation for Y = 8.
5 * (3 * 8 - 2) = 15 * 8 - 10
5 * (24 - 2) = 120 -10
5 * 22 = 110
110 = 110
Solving the equation for Y = 9.
5 * (3 * 9 - 2) = 15 * 9 - 10
5 * (27 - 2) = 135 -10
5 * 25 = 125
125 = 125
This proves that the equation holds good for at least 5 values of 'y', which are 1, 2, 4, 8 and 9.
However, it can be proved that the equation holds good for any value of y.
Expression 5(3y-2) can be simplified to 15y -10 which is the same expression on the right had side of the equation provided.
So, equation 5(3y-2)=15y-10 is actually 15y-10=15y-10 and since this is true for all values of y, it has been proved that it is true for at least 5 values of y.</span>
Answer:
The triangles are the same though, what do i do?
Step-by-step explanation:
Answer:
6x^2 -10
Step-by-step explanation:
(5x²+2) - (-4x²+7)+(-3x²-5)
Distribute the minus sign
(5x²+2) +4x²-7 +(-3x²-5)
Combine like terms
5x²+4x²-3x² +2-7-5
6x^2 -10
Answer:
The man wins 9 times and looses 11 times in the rock - paper-scissor game.
Step-by-step explanation:
Let us assume that in the game:
Number of times man wins the games = x times
Number of times man loses the games = y times
Total number of attempts = 20
Points after winning = 5
Points after loosing = 2
Now, according to the question:
x + y =20
and 5 x + 2 y = 67
Now, from (1) y = 20-x, put in (2)
5x + 2y = 67 ⇒ 5x + 2(20 -x) = 67
or, 5x -2x = 67 - 40
or, 3x = 27
⇒ x = 27/3 = 9
then y = 20 - x = 20 - 9 = 11
⇒ x = 9 and y = 11 is the solution of the given system.
Hence, the man wins 9 times and looses 11 times in the rock - paper-scissor game.
