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4 years ago

223 divided by 26 with the remainder

Mathematics

1 answer:

harina [27]4 years ago

5 0

Answer: 8 with the remainder of 25

Step-by-step explanation:

26 can go into two 0 times. 2-0=2 bring down the 3. 26 can go into twenty-three 0 times. 23-0=23 bring down the 3 now u have 233. 26 can go into 233--> 8. Subtract 233-208=25

Answer: 8 R 25

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3 years ago

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4 years ago

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3 years ago

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3 years ago

Please help me!!!!!!!!!!!!!

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Answer: see proof below

<u>Step-by-step explanation:</u>

Use the following Half-Angle Identities: tan (A/2) = (sinA)/(1 + cosA)

cot (A/2) = (sinA)/(1 - cosA)

Use the Pythagorean Identity: cos²A + sin²B = 1

Use Unit Circle to evaluate: cos 45° = sin 45° = $\frac{\sqrt2}{2}$

<u>Proof LHS → RHS</u>

Given: $cot\ (22\frac{1}{2})^o-tan\ (22\frac{1}{2})^o$

Rewrite Fraction: $cot\ (\frac{45}{2})^o-tan\ (\frac{45}{2})^o$

Half-Angle Identity: $\dfrac{sin(45)^o}{1-cos(45)^o}-\dfrac{sin(45)^o}{1+cos(45)^o}$

Substitute: $\dfrac{\frac{\sqrt2}{2}}{1-\frac{\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{1+\frac{\sqrt2}{2}}$

Simplify: $\dfrac{\frac{\sqrt2}{2}}{\frac{2-\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{\frac{2+\sqrt2}{2}}$

$=\dfrac{\sqrt2}{2-\sqrt2}-\dfrac{\sqrt2}{2+\sqrt2}$

$=\dfrac{\sqrt2}{2-\sqrt2}\bigg(\dfrac{2+\sqrt2}{2+\sqrt2}\bigg)-\dfrac{\sqrt2}{2+\sqrt2}\bigg(\dfrac{2-\sqrt2}{2-\sqrt2}\bigg)$

$=\dfrac{2\sqrt2+2}{4-2}-\dfrac{2\sqrt2-2}{4-2}$

$=\dfrac{4}{2}$

= 2

LHS = RHS: 2 = 2 $\checkmark$

7 0

4 years ago