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3 years ago

What is one as a percent

Mathematics

2 answers:

aev [14]3 years ago

8 0

Answer:

0.01%

Step-by-step explanation:

1 is also 1.00

To get a number to percent form you move the demicial point (.) 2 times to the left.

Then you get 0.01%

olga2289 [7]3 years ago

4 0

Answer:

One as a percent is 0.01%

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3 years ago

You put $800 in an account that earns 4% simple interest. Find the total amount in your account after each year for 3 years. (Pl

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To get 4% of 800 you times 800 by 4 and divide it by 100. Once you have that amount you add it to 800 to find the amount you will have in your bank the first year. To get the next year's amount you then get 4% of 832(because after the first year you have more than $800) and then add the 4% to 832, that is the answer for the second year. To find the third year's amount you get 4% of the new amount (last year's total) and add it to last year's total, that is your total for the third year. So the first year will be: (800x4÷100)+800 =32+800 =832 The second year will be: 832+(832x4÷100) =832+33.28 =865.28 The third year will be: (865.28×4÷100)+865.28 =34.61(rounded off)+865.28 =899.89

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4 years ago

Read 2 more answers

When I sit and watch my students take exams, I often think to myself "I wonder if students with bright calculators are impacted

hodyreva [135]

Answer:

There is a difference between the two means.

Step-by-step explanation:

The hypothesis can be defined as:

H₀: The mean exam scores of my SAT 215 students with colorful calculators are same as the mean scores of my STA 215 students with plain black calculators, i.e. μ₁ - μ₂ = 0.

Hₐ: The mean exam scores of my SAT 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators, i.e. μ₁ - μ₂ ≠ 0.

Assume that the significance level of the test is, α = 0.05. Also assuming that the population variances are equal.

The decision rule:

A 95% confidence interval for mean difference can be used to determine the result of the hypothesis test. If the 95% confidence interval contains the null hypothesis value, i.e. 0 then the null hypothesis will not be rejected.

The 95% confidence interval for mean difference is:

$CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}$

Compute the pooled standard deviation as follows:

$S_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}} {n_{1}+n_{2}-2}}}=\sqrt{\frac{(49-1)(4.7)^{2}+(38-1)(5.7)^{2}}{49+38-2}}=5.16$

The critical value of t is:

$t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.05/2, (49+38-2)}=t_{0.025, 85}=1.984$

*Use a t-table.

Compute the 95% confidence interval for mean difference as follows:

$CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}$

$=(84-87)\pm 1.984\times 5.16\times \sqrt{\frac{1}{49}+\frac{1}{38}}$

$=-3\pm 2.133\\=(-5.133, -0.867)\\\approx(-5.13, -0.87)$

The 95% confidence interval for mean difference is (-5.13, -0.87).

The confidence interval does not contains the value 0. This implies that the null hypothesis will be rejected at 5% level of significance.

Hence, concluding that the mean exam scores of my STA 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators.

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3 years ago

Please help I am terrible at algebra

Marina CMI [18]

Answer:

y = (x-0)^2 + (-5) ⇒ y = x^2 - 5

Step-by-step explanation:

The general vertex form of the parabola y = a(x - h)² + k

Where (h,k) is the coordinates of the vertex.

As shown at the graph the vertex of the parabola is the point (0, -5)

So,

y = a(x-0) + (-5)

y = ax^2 - 5

To find substitute with another point from the graph like (1,-4)

So, at x = 1 ⇒ y = -4

-4 = a * 1^2 - 5

a = -4 + 5 = 1

So, the equation of the given parabola is ⇒ y = x^2 - 5

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3 years ago