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2 years ago

How do you tell if there is an infinite amount of solutions?

Mathematics

1 answer:

scoray [572]2 years ago

5 0

Answer:

i fell good

Step-by-step explanation:

becuase some are sooo easy

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SEPTEMBER 2016 (GP HYPERBOLA)

kirill115 [55]

Answer:

we dont have all the information and dont know the question

5 0

2 years ago

A bottle contains 5/9 liters of soda. Keisha has 3 of these bottles.

satela [25.4K]

Answer: 1 2/3 Liters

Step-by-step explanation:

Create the equation

The equation is going to be the amount of soda, multiplied by the amount of bottles Keisha has

5/9 x 3/1 (3/1 is equivalent to having 3 or 1+1+1)

Solve

We are going to multiple the numbers, numerator by numerator, and denominator by denominator since we do not need to add or subtract

Numerator= 5x3=15
Denominator= 9x1=9

Your improper awnser would be 15/9

DO NOT STOP HERE THIS IS NOT THE SIMPLEST FORM

Create the simplest mixed number

15/9 is equal to 15 divided by 9

we can fit 1 9 in 15 without going over

1 ?/15

15-9=6

1 6/9

Simplify

6 and 9 are both divisible by 3

6 divided by 3 = 2

9 divided by 3 = 3

1 6/9=1 2/3

Awnser and add your units

1 2/3 is the simpelest form, this can not be further divided.

1 2/3 Liters of Soda

3 0

2 years ago

Which number is not a rational number?

Valentin [98]

Rational is a number that can be expressed as a ratio of two in tegers where denominator is not equal to 0 is called a rational number.

4 0

2 years ago

D Evaluate arcsin (6)] at x = 4. dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

2 years ago

PLZZZ HELPP anyonee plzzzz

mihalych1998 [28]

Answer:

The correct answer is B

Step-by-step explanation:

its is B because when dividing fractions the division symbol changes into a multiplication sign and the fraction on the right flips

High Hopes^^

Barry-

8 0

3 years ago

Read 2 more answers