1) there isn't a picture
2) you are offering 7 points
3) your points are already wasted i guess
Answer:
System has equal number of unknowns and equations.
Manipulation easily yielded expressions for 4 of the 7 unknowns.
However it seems that the remaining 3 unknowns x,y,z are not fixed by the equations. Different combinations (x0,y0,z0) seem possible without violating the system equations.
Is this possible, or did I most probably make a mistake in counting degrees of freedom?
Step-by-step explanation:
Answer:11
Step-by-step explanation:
x^2-108 =13
+108 +108
x^2=121
2√x= √121
x=11
You need to divide 122 by 10, then you multiply your answer by 10 and see if you get 122. So 122 divided by 10 = 12.2, then 10 x 12.2= 122.
We will usePythagorean theorem
a^2+b^2=C^2
Lets substitute and solve
2^2+b^2=3^2
4+b^2=9 lets subtract 4
b^2=5
b=√5 or 2.2360679775
