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Thepotemich [5.8K]
3 years ago
6

Complete everything in the photo you may have to download it. plz DO NOT WASTE MY POINTS.

Mathematics
1 answer:
True [87]3 years ago
7 0

1) there isn't a picture

2) you are offering 7 points

3) your points are already wasted i guess

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The grades on a physics midterm at Covington are roughly symmetric with = 72 and = 2.0. Stephanie scored 74 on the exam. Find th
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Answer:1.00

Step-by-step explanation:

A=74-72/2.0

And I did it on kahn

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Nine times a number
guapka [62]

Answer:

if we do 9 times a number that will be

9x

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Is the equation -x=1-y and 2+y=x+1 coincident, intersecting, or parallel
yarga [219]
\bf x=1-y\implies x+y=1\implies y=-x+1\\\\
-------------------------------\\\\
2+y=x+1\implies y=x+1-2\implies y=x-1

notice the equations in slope-intercept form, the first one has a slope of -1, the second one has a slope of 1.

if the slopes are equal, and the constant is different, they lines are parallel.

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4 0
3 years ago
Look at the picture question and answer in there
nignag [31]

x-intercept is for y = 0

y-intercept is for x = 0

We have x - 3y = -9.

Put y = 0 to the equation:

x - 3(0) = -9

x - 0 = -9

x = -9

Put x = 0 to the equation:

9 - 3y = -9

-3y = -9       <em>divide both sides by (-3)</em>

y = 3

Answer:

<h3>x-intercept (-9, 0); y-intercept (0, 3)</h3>
8 0
3 years ago
Find the value of cosAcos2Acos3A...........cos998Acos999A where A=2π/1999
Lady bird [3.3K]
Hello,

Here is the demonstration in the book Person Guide to Mathematic by Khattar Dinesh.

Let's assume
P=cos(a)*cos(2a)*cos(3a)*....*cos(998a)*cos(999a)
Q=sin(a)*sin(2a)*sin(3a)*....*sin(998a)*sin(999a)

As sin x *cos x=sin (2x) /2

P*Q=1/2*sin(2a)*1/2sin(4a)*1/2*sin(6a)*....
         *1/2* sin(2*998a)*1/2*sin(2*999a) (there are 999 factors)
= 1/(2^999) * sin(2a)*sin(4a)*...
     *sin(998a)*sin(1000a)*sin(1002a)*....*sin(1996a)*sin(1998a)
 as sin(x)=-sin(2pi-x) and 2pi=1999a

sin(1000a)=-sin(2pi-1000a)=-sin(1999a-1000a)=-sin(999a)
sin(1002a)=-sin(2pi-1002a)=-sin(1999a-1002a)=-sin(997a)
...
sin(1996a)=-sin(2pi-1996a)=-sin(1999a-1996a)=-sin(3a)
sin(1998a)=-sin(2pi-1998a)=-sin(1999a-1998a)=-sin(a)

So  sin(2a)*sin(4a)*...
     *sin(998a)*sin(1000a)*sin(1002a)*....*sin(1996a)*sin(1998a)
= sin(a)*sin(2a)*sin(3a)*....*sin(998)*sin(999) since there are 500 sign "-".

Thus
P*Q=1/2^999*Q or Q!=0 then
P=1/(2^999)

       








7 0
3 years ago
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