Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
Answer:
θ ≈ 71.6°
Step-by-step explanation:
The angle between two lines with slopes m₁ and m₂ is:
tan θ = | (m₂ − m₁) / (1 + m₁m₂) |
Here, m₁ = -2 and m₂ = 1.
tan θ = | (1 − (-2)) / (1 + (-2)(1)) |
tan θ = | 3 / -1 |
tan θ = 3
θ ≈ 71.6°
Answer:
80 cents
Step-by-step explanation:
The easiest place to start for this is to calculate how much it costs per minute of call time. To do this, if we know that it costs 52.5 cents to call for 3.5 minutes, we can divide those two numbers to get how much it costs per minute.
52.5/3.5 = 15
If it costs 15 cents per minute, and we want to know how much it would cost to call for 5.33 (5 and 1/3 of a minute), then we multiply our 15 cents a minute by the number of minutes to get the final cost.
15 x 5.33 = 79.99
Because we can't have 99/100 cents, rounding up to 80 is important to get a proper answer.
