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photoshop1234 [79]
3 years ago
14

In a random sample of 625 people, it was found that 225 of them frequently check their work email when they are at home. Find th

e upper confidence limit of a 95% confidence interval for p, the true proportion of people who frequently check their work email when they are at home. Give your answer to four decimal places
Mathematics
1 answer:
VMariaS [17]3 years ago
4 0

Answer: (0.3224,0.3976)

Step-by-step explanation:

Given : Sample size : n=625

Number of people check their work email when they are at home =225

The probability of people check their work email when they are at home :p=\dfrac{225}{625}=0.36

Significance level : \alpha:1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

The confidence interval for population proportion is given by :-

p \pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.36\pm(1.96)\sqrt{\dfrac{0.36(1-0.36)}{625}}\\\\=0.36\pm0.037632\\\\=(0.322368,0.397632)\approx(0.3224,0.3976)

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Answer:

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Step-by-step explanation:

Juan practiced the violin for 9 hours last week. For each 3 hours that he practices the violin, he practices 2.5 hours of cello. So

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3x = 9*2.5

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3 years ago
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\huge\text{Hey there!}

\huge\text{x + x(x + y) + y}

\huge\text{= 4 + 4(4 + 1) + 1}

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\huge\text{= 25}

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