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N76 [4]
3 years ago
8

On a given planet, the weight of an object varies directly with the mass of the object. Suppose that an object whose mass is 9 k

g weighs 45 N. Calculate the mass of another object that weighs 30 N.
Mathematics
1 answer:
nadya68 [22]3 years ago
5 0

Answer:

6 kg

Step-by-step explanation:

Given is weight of an object directly varies with the mass of the object .

Let the constant of proportionality be k

So,

Weight = K×(mass of the object)

For an object , weight = 45 N

                        mass = 9 kg

So , 45 = K×9

      K = 5.

Now, for the other object ,

Weight = 30 N. K = 5 (as obtained above)

So, 30 = 5×(mass of the object)

mass of the object = 6 kg.

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Lucy cuts 4 squares with side length x in. From the corners of a 6 in. By 9 in. Cardboard rectangle. She folds the remaining car
Fittoniya [83]

Answer:

4x³ - 30x² + 54x

Step-by-step explanation:

Length of the rectangular cardboard = 9 inches

Width of the rectangular cardboard = 6 inches

if the square of sides x inches is cut from each corner of the rectangular cardboard and folded to make a tray, then we have

Length of the tray = length of cardboard - 2(side of square )

= 9 - 2x

Width of the tray = width of cardboard - 2( side of square)

= 6 - 2x

height of tray = sides of square

= x

volume of tray = Length × width × height

= (9 - 2x) (6 - 2x) (x)

Open the parenthesis

= (54 - 18x - 12x + 4x²)(x)

= 54x - 18x² - 12x² + 4x³

= 54x - 30x² +4x³

Re-arrange

4x³ - 30x² + 54x

Volume, V of the tray in terms of x = 4x³ - 30x² + 54x

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Step-by-step explanation:{-1,0,1}Intersects[-1,1]=__0__

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A piano that cost Sunset Planos 83, 250 has a markup rate of 52%. Find the selling price of the piano
Yanka [14]

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$160,096.15

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Y/5-2=-7 what is the solution of the equation.
Virty [35]

Answer: mg they left u hanging for some time here hol up,

y=−25

Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    y/5-2-(-7)=0

y/5          

(y/5 -  2) -  -7  = 0  

Subtracting a whole from a fraction

Rewrite the whole as a fraction using  5  as the denominator :

       

   2 =  2/1=2.5/5

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

y - (2.5/5 5)=y - 10

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 y+25

 ———— • 5 = 0 • 5

  5  

Now, on the left hand side, the  5  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  y+25  = 0

4.2      Solve  :    y+25 = 0  

Subtract  25  from both sides of the equation :  

                     y = -25

 

8 0
3 years ago
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