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Nadusha1986 [10]
3 years ago
14

What is 2.45 in fraction form

Mathematics
1 answer:
slamgirl [31]3 years ago
4 0
2.45 = 245/100 = 49/20 = 2 9/20 

hope this helps :-)







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A sum of money is invested for 3 years at a certain rate of interest. Had the rate of interest been 1 %more it would have fetche
Allisa [31]

Answer:  the sum invested = $600

<u>Step-by-step explanation:</u>

Interest (I) = Principal (P) × rate (r) × time (t)

Original amount: I = P × r × 3

Increased by 1%: I + 18 = P × (1+ .01)r × 3

Substitute I with Prt and set the equations equal to each other to find r:

3Pr + 18 = 3.03Pr

Solve for Pr:

         18 = 0.03Pr

<u>    ÷0.03</u>   <u>÷ 0.03   </u>

      600 = Pr  

6 0
3 years ago
There are 13 cards of each suit in a deck of 52 cards (13 hearts, 13 diamonds, etc.). What is the probability of
lord [1]

We want to find the probability of randomly drawing a diamond card from a standard deck. We will find that the probability is P = 1/4.

So because we draw a card randomly, every card has the same probability of being drawn. Then the probability of randomly drawing a diamond card is equal to the quotient between the number of diamond cards and the total number of cards.

There are 13 diamond cards and a total of 52 cards, then the probability is:

P = 13/52 = 1/4

If you want to learn more about probability, you can read:

brainly.com/question/15246027

5 0
2 years ago
Round 8.1165 to the nearest hundredth.​
Yakvenalex [24]

Answer:

8.12

Step-by-step explanation:

Hey There!

When you round to the nearest hundredth you are rounding the number 2 digits away from the decimal point which is 1

remember we base the rounding off of the number after 1 which is 6

5 or more raise the score

so 8.1165 rounded to the nearest hundredth would be

8.12

7 0
3 years ago
Read 2 more answers
Suppose ACT Reading scores are normally distributed with a mean of 21.3 and a standard deviation of 5.9. A university plans to a
Mekhanik [1.2K]

Answer:

30.0

Step-by-step explanation:

Given our data is normally distribute with \mu=21.3 and \sigma=5.9

-Top 7% is given by find the z-value corresponding to p=(1-0.07)=0.93

-We substitute our values in the equation below;

z=\frac{\bar X-\mu}{\sigma}\\\\\\=\frac{X-21.3}{5.9}, z_{0.035}=1.476\\\\\therefore 1.476=\frac{X-21.3}{5.9}\\\\X=5.9\times 1.476+21.3\\\\=30.0084\approx30.0

Hence, the minimum score required for the scholarship is 30.0

8 0
3 years ago
Can you please help me with this i don’t understand
Alinara [238K]

Answer:

  (5, 2)

Step-by-step explanation:

<h3>understanding the question</h3>

The question is asking you to express the temperature at 5 pm as a pair of graph coordinates.

Doing this requires that you ...

  • read from the graph the temperature at 2 pm
  • read from the graph the temperature at 8 pm
  • figure the temperature halfway between those values
  • express the 5 pm temperature as an ordered pair (hours, °C)

__

<h3>reading the graph</h3>

The description of the graph tells you the horizontal scale is hours after noon, so the temperature at 2 pm will be a point on the graph with an x-coordinate of 2. That point is (2, 7), indicating the temperature at 2 pm is 7 °C.

Likewise, the temperature at 8 pm is shown as the point on the graph with x-coordinate 8. That point is (8, -3), indicating a temperature of -3°C at 8 pm.

<h3>halfway temperature</h3>

The temperature halfway between those values (7 °C and -3 °C) can be found several ways. Perhaps the easiest is to average the values:

  (7 +(-3))/2 = 4/2 = 2

The temperature at 5 pm is 2 °C.

<h3>coordinates</h3>

Coordinates on the graph are ordered pairs of the form (x, y) = (hours, °C). The time 5 pm is 5 hours after noon, so the x-coordinate is 5. The temperature at 5 pm is halfway between the temperatures at 2 and 8 pm, which we have computed to be 2 °C, so the y-coordinate is 2.

The coordinates that represent the temperature at 5 pm are ...

  (5, 2)

6 0
2 years ago
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