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lord [1]
2 years ago
8

What are the ratios for SIN A and COS A

Mathematics
1 answer:
miskamm [114]2 years ago
6 0

Answer:

A

Step-by-step explanation:

A good trick for trigonometric functions is to remember SOHCAHTOA:

Sin=<u>O</u>pposite over <u>H</u>ypotenuse

Cos=<u>A</u>djacent over <u>H</u>ypotenuse

Tan=<u>O</u>pposite over <u>A</u>djacent

The red arrows on the attachment indicate where opposite, hypotenuse, and adjacent are for angle A.

So in this case, the sin of angle A (opposite over hypotenuse) would be \frac{24}{26} and cos A (adjacent over hypotenuse) would be \frac{10}{26}.

I hope this helps!

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Answer:

False

Step-by-step explanation:

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2 years ago
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#19. state the possible number of imaginary numbers of f(x) = 7x3 - x2 + 10x - 4
guapka [62]
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3 years ago
HELP! ASAP! Am I correct!?!?
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3 years ago
A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.
Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h(t)=-48t -16t^2. We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula x=-\frac{b}{2a}.

x=-\frac{-48}{2(-16)}

x=-\frac{48}{32}

x=-\frac{3}{2}

So, the x-coordinate of the parabola is -\frac{3}{2}. Now, we will substitute x=-\frac{3}{2} in our given equation to find y-coordinate of parabola.

h(t)=-48t -16t^2

h(-\frac{3}{2})=-48(-\frac{3}{2})-16(-\frac{3}{2})^2

h(-\frac{3}{2})=-24(-3)-16(\frac{9}{4})

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h(-\frac{3}{2})=36

Therefore, the maximum height of the ball is 36 feet.

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3 years ago
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