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vovikov84 [41]
3 years ago
14

Given Q'R'S'T' is a dilation of QRST, find the scale factor of dilation.

Mathematics
1 answer:
Kobotan [32]3 years ago
5 0

Answer:

5Cause 15 divided by 3 is five

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The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance betw
shusha [124]
We know that
circumference=2*pi*r-------> r=circumference/(2*pi)
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r=circumference/(2*pi)------> 30/(2*pi)-----> 4.7746 in
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</span>
<span>the distance between the ball and the rim is equal to
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radius of a basketball rim =18/2------> 9 in
radius of a a standard basketball=4.77 in<span>

</span>
the distance between the ball and the rim=[9-4.77]------> 4.23 in

the answer is
4.23 in
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B

Step-by-step explanation:

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