I. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point.
So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL
ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the steps
Answer:
f(2) =30
Step-by-step explanation:
f(1)=15
f(n)=f(n-1)*n
Put in n=2
f(2)=f(2-1)*2
= f(1) *2
= 15*2
=30
The first thing we should do is write the functions.
For the area we have:
A = w * h = 20000 feet ^ 2
The price is:
Cost = (4 * 2 * h + 2 * 2 * w)
Substitute for h ::
C (w) = (4 * 2 * (20,000 / w) + 2 * 2w)
Rewrite we have:
C (w) = 160,000 / w + 4w
Take the derivative:
C '(w) = 160000 (-1 / w ^ 2) + 4
We equal zero and clear w:
0 = 160000 (-1 / w ^ 2) + 4
160000 / w ^ 2 = 4
w ^ 2 = 40000
w = 200 (approximately)
width = 200 ft; so cost is 2 * ($ 4) 200 = $ 1600
height = 20000/200 = 100 ft; so cost is 2 ($ 2) 100 = $ 400
Total cost = $ 2000
Answer:
The cost of the least expensive fence is:
Total cost = $ 2000
Answer:(2,1/3)
Step-by-step explanation:
-x-3y=-3
2x+3y=5
_________First solve for x since y is 0. -3y+3y=0
1X = 2
1x/1= 2/1
X= 2
Now substitute your x answer into any equation to find y I used second equation
2x+3y= 5
2(2)+3y=5
4+3y=5
3y=5-4
3y=1
3y/3=1/3
Y=1/3
