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Alina [70]
3 years ago
14

0/1

Mathematics
1 answer:
USPshnik [31]3 years ago
3 0

Answer:

1 \sqrt{2}

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Using the triangle 45o -45o -90o theorem solve this triangle. please​
Zarrin [17]

Answer:

The length of the leg is 11 units.

Step-by-step explanation:

The triangle 45 - 45 - 90 theorem states that the length of the hypotenuse is \sqrt{2} times of the length of any of the legs. Hence, we get the following expression:

h = \sqrt{2} \cdot l (1)

Where:

l - Length of the leg, in units.

h - Hypotenuse, in units.

If we know that h = 11\sqrt{2}, then the length of the leg is:

l = \frac{h}{\sqrt{2}}

l = 11

The length of the leg is 11 units.

6 0
3 years ago
Mikes checking account pays 0.5% interest monthly and has a $7.50 service fee. If mikes balance last month was $1423, find the a
wlad13 [49]
1. Take Mike's total from last month and add it up with the service fee. ($1423 + $7.50)
2. 1430.5 is your total, then multiply that by .5% for intrest fee. Intrest fee is $7.153
3. You take $1430.5 + $7.153
TOTAL. $1437.65

Hope this helped.


YOUR QUESTION

Mikes checking account pays 0.5% interest monthly and has a $7.50 service fee. If mikes balance last month was $1423, find the amount of credit or debit to his account after interest and service fee are both applied.
5 0
3 years ago
Read 2 more answers
Y’all should pls help I rlly need help, and if you can pls explain how to do it cause I’m confuseeeed! :)
OLEGan [10]

Answer:

C

Step-by-step explanation:

1/3(pi) times the radius (3,because its half of 6) squared, times height (10) gives you 94.24777.... which is equivalent to C

8 0
3 years ago
Write an absolute value equation for the graph shown below
BabaBlast [244]
So, hmmm keeping in mind that, an absolute value expression is in effect a piece-wise function, let's find its "slopes", the negarive slope on the left-side and the positive slope on the right side, and let's use the vertex point as our first point

what is the slope of a line that passes through (2, -1) and (0,7)

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 2}}\quad ,&{{ -1}})\quad 
%   (c,d)
&({{ 0}}\quad ,&{{ 7}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{7-(-1)}{0-2}\implies \cfrac{7+1}{-2}\implies -4
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-1)=-4(x-2)
\\\\\\
\boxed{y+1=-4(x-2)}

now, what is the slope of a line that passes through (2, -1) and (4,7)

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 2}}\quad ,&{{ -1}})\quad 
%   (c,d)
&({{ 4}}\quad ,&{{ 7}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{7-(-1)}{4-2}\implies \cfrac{7+1}{2}\implies 4
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-1)=4(x-2)
\\\\\\
\boxed{y+1=4(x-2)}

since an absolute value expression is just a piece-wise with a +/- versions, then we can just combine those two.

\bf \begin{cases}
y+1=-4(x-2)\\
y+1=4(x-2)
\end{cases}\implies y+1=\pm 4(x-2)
\\\\\\
y+1=|4(x-2)|\implies y=|4(x-2)|-1
7 0
3 years ago
Will give brainliest
hoa [83]

Answer:

3,1,2

Step-by-step explanation:

I think it is 3,1,2 but I'm not completely sure lmk if it's correct or incorrect

~

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∧_∧

;;(´・ω・)

_旦_(っ(,,■)__

|l ̄l|| ̄じじ ̄|

6 0
3 years ago
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