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Alina [70]
3 years ago
14

0/1

Mathematics
1 answer:
USPshnik [31]3 years ago
3 0

Answer:

1 \sqrt{2}

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Hi, i need help with these questions!
MA_775_DIABLO [31]
I hope this helps you

6 0
4 years ago
a line goes through the point(6,-2)and has a slope of -3 what is the value of a if the point (a,7) lies on the line​
yaroslaw [1]

Answer:

The value of a is "3", to complete the coordinate point (3,7) on the line.

Step-by-step explanation:

We are given the slope of the line, and also one point through which the line passes. Therefore, we can find the actual equation of the line by using the slope-point form of the line:

y-y_0=m(x-x_0)\\y-(-2)=(-3)(x-6)\\y+2=-3x+18\\y=-3x+18-2\\y=-3x+16

Now, we need to find which value of "x" renders a y-value of "7", to complete the coordinate pair (a, 7) as requested. Therefore, we ask for the y-value in the previous equation to be "7", and solve for its associated x-value:

y=-3x+16\\7=-3x+16\\7-16=-3x\\-9=-3x\\x=\frac{-9}{-3} \\x=3

Therefore, x = 3

3 0
3 years ago
Read 2 more answers
ANSWER ASAP!! Write an equation that represents the line. Please make sure your answer is the exact numbers!
Citrus2011 [14]

Answer:

y=7/5x+7

Step-by-step explanation:

Use the saying "rise over run" to find the slope. If we go from the bottom most  dot, we have to rise 7 and run 5 to reach the next dot, making the slope 7/5.

Next, we have to find the y-intercept. Do this by locating where the line crosses the y-axis, in this case it is at 7.

Finally, plug these numbers into slope-intercept format: y=mx+b (m is slope, and b is y-intercept).

3 0
3 years ago
these numbers form an addition and subtraction fact family for 6,7,13 here the choices 7+13=20 13+7=20 13-13=0 13-0=13 and 7+0=7
Dominik [7]

Answer:

its the first one

Step-by-step explanation:

Ive had this question before

3 0
3 years ago
Find the product of<br><br>(1 + sinA) (1 + sinA) (1 + sinA)<br><br>helppp<br>​
katovenus [111]

Answer:

1 + 3sinA + 3sin²A + sin³A

Step-by-step explanation:

Given

(1 + sinA)(1 + sinA)(1 + sinA) ← expand the last pair using FOIL

= (1 + sinA)(1 + 2sinA + sin²A) ← distribute

= 1 + 2sinA + sin²A + sinA + 2sin²A + sin³A ← collect like terms

= 1 + 3sinA + 3sin²A + sin³A

8 0
3 years ago
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