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OleMash [197]
3 years ago
15

From a survey taken several years ago, the starting salaries of individuals with an undergraduate degree from Business Schools a

re normally distributed with a mean of $40,500 and a standard deviation of $4,500.What is the probability that a randomly selected individual with an undergraduate business degree will get a starting salary of at least $36,000.00? (Round your answer to 4 decimal places.)
Mathematics
1 answer:
Klio2033 [76]3 years ago
8 0

Answer: 0.8413

Step-by-step explanation:

Given: Mean : \mu=\$40,500

Standard deviation : \sigma = \$4,500

The formula to calculate z-score is given by :_

z=\dfrac{x-\mu}{\sigma}

For x= $36,000.00, we have

z=\dfrac{36000-40500}{4500}=-1

The P-value = P(z\geq-1)=1-P(z

Hence, the probability that a randomly selected individual with an undergraduate business degree will get a starting salary of at least $36,000.00 = 0.8413

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