Answer:
x--------------y
4--------------2
8--------------3
12-------------4
Step-by-step explanation:
y = 1/4x + 1
We substitute the values under x into the equation
Equation 1: y = 1/4(4) + 1
Equation 2: y = 1/4(8) + 1
Equation 3: y = 1/4 (12) + 1
Let's solve for equation 1:
Equation 1: y = 1/4(4) + 1
y = 1/4(4) + 1
Multiply number in parenthesis
y = 1/4 * 4/1 + 1
1/4 and 4/1 turn into 1
y = 1 + 1
Add 1 to 1
y = 2
Let's solve for equation 2:
y = 1/4(8) + 1
Multiply number in parenthesis
y = 1/4 * 8/1 + 1
1/4 and 8/1 turn into 2
y = 2 + 1
Add 2 to 1
y = 3
Let's solve for equation 3:
y = 1/4 (12) + 1
Multiply number in parenthesis
y = 1/4 * 12/1 + 1
1/4 and 12/1 turn into 3
y = 3 + 1
Add 3 to 1
y = 4
So the table of values would be:
x--------------y
4--------------2
8--------------3
12-------------4
look at the graph
180×0.05=9
So 5% of 180 is 9
Answer:
D) 8.1 m
Step-by-step explanation:
Area of a circle is pi r^2
Answer:
x>-12
Step-by-step explanation:
x/-2-4<2
x/-2<2+4
x/-2<6
x<6(-2)
x<-12
x>-12
Answer:
7.86 km
Step-by-step explanation:
Let x represent the distance point P lies east of the refinery. (We assume this direction is downriver from the refinery.)
The cost of laying pipe to P from the refinery (in millions of $) will be ...
0.5√(1² +x²)
The cost of laying pipe under the river from P to the storage facility will be ...
1.0√(2² +(9-x)²) = √(85 -18x +x²)
We want to minimize the total cost c. That total cost is ...
c = 0.5√(x² +1) +√(x² -18x +85)
The minimum value is best found using technology. (Differentiating c with respect to x results in a messy radical equation that has no algebraic solution.) A graphing calculator shows it to be at about x ≈ 7.86 km.
Point P should be located about 7.86 km downriver from the refinery.
