Answer:
a) 236/100 = 2.36
b) 101/100 = 1.01
c) 814/100 = 8.14
Step-by-step explanation:
The divisor in each case is already a factor of 100, so multiply the numerator and denominator by the number that will make the denominator 100. Then add 100 times the integer to the numerator of the fraction.
a) 2 9/25 = (200 +9·4)/(25·4) = 236/100 = 2.36
b) 1 1/100 = (100 +1)/100 = 101/100 = 1.01
c) 8 7/50 = (800 +7·2)/(50·2) = 814/100 = 8.14
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Since each of these fractions has a denominator of 100, the decimal can be written by putting the least significant digit of the numerator in the hundredths place of the decimal number.
For example, for 236/100, putting 6 in the hundredths place puts 3 in the tenths place and 2 in the units place for a decimal number of 2.36.
The capacity of the tank in gallons is 24 gallons.
<h3>What is an Equation ?</h3>
An equation is a mathematical statement formed when two algebraic expressions are equated by an equal sign.
It is given in the question that
When four gallons are added to a tank that is one-third full
the tank is then one-half full.
Let the capacity of the tank is x gallons
The equation can be formed for the capacity of the tank as
(1/3)x +4 = (1/2)x
(1/3)x -(1/2)x = -4
(1/6)x = 4
x = 24 gallons.
Therefore the capacity of the tank in gallons is 24 gallons.
To know more about Equation
brainly.com/question/2263981
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the equation of a line in point-slope form is
y - b = m(x - a)
where m is the slope and (a, b ) is a point on the line
y + 1 =
(x + 5) is in this form
(a) with slope = 
(b) point on the line = (- 5, - 1 ) = (a, b)
Answer:
2.5 × 10^-5
<em>please correct me if im wrong</em><em>.</em>
Answer:
the first one
Step-by-step explanation:
A graph showing the Earliest Start Times (EST) for project tasks is computed left to right based on the predecessor task durations. For dependent tasks, the earliest start time will be the latest of the finish times of predecessor tasks.
The first graph appears to appropriately represent the table values, using edges to represent task duration, and bubble numbers to represent start times.
The second graph does not appropriately account for duration of predecessor tasks.
The third graph seems to incorrectly compute task completion times (even if you assume that the edge/bubble number swap is acceptable).