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Kamila [148]
3 years ago
6

Use substitution to solve the system. x = 2y +13 - 2x + 3y = -21

Mathematics
1 answer:
il63 [147K]3 years ago
7 0
The answer is
(x,y) = (3,-5)
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I am a rectangle, and my area is 80 square inches. My width is 2 inches shorter than my length. What is my perimeter?
pshichka [43]
Area=l*b=l*(l-2)=80(given)

so, l^2 - 2l =80
   l^2 - 2l - 80=0
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l=10,b=10-2=8
perimeter=2(l+b)=2(18)=36
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Solve for m 1/C+1/m=1/z
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Answer:  " m = zC / (C − z) " .
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Explanation:
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Given:  1/C + 1/m = 1/z ;  Solve for "m".

Subtract  "1/C" from each side of the equation:
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1/C + 1/m − 1/C = 1/z − 1/C  ;

to get:  1/m = 1/z − 1/C ;
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Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
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mzC {1/m = 1/z − 1/C} ;

to get:  zC = mC − mz ;

Factor out an "m" on the "right-hand side" of the equation:

zC = m(C − z) ;  Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;

zC / (C − z) = m(C − z) / m ;  to get:   24/8 = 3  24

zC/ (C − z) = m ;   ↔   m = zC/ (C − z) .
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3 years ago
Find the solution of the square root of the quantity of x plus 2 plus 4 equals 8, and determine if it is an extraneous solution
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Consider the equation:

\sqrt{x+2}+4 = 8

Subtracting '4' from both the sides of the equation, we get as

\sqrt{x+2}+4-4= 8-4

\sqrt{x+2}= 4

Squaring on both the sides of the equation, we get

(\sqrt{x+2})^2 = (4)^2

x+2 = 16

Subtracting '2' from both the sides of the equation, we get

x+2-2=16-2

x=14

Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.

Hence, it is not an extraneous solution.

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Which of the following relations is not a function?
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B but I'm not as sure though

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