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Brrunno [24]
4 years ago
14

What are inner transition metals composed of?

Chemistry
2 answers:
Solnce55 [7]4 years ago
8 0

Answer:

Lanthanides and actinides

Explanation:

i did the test

strojnjashka [21]4 years ago
3 0

Answer:

Lanthanides and actinides

Explanation:

The inner transition metals consist of two series called lanthanides and actinides.

These are f block elements.

The lanthanide series having elements with atomic number 58-71. These are 14 elements.

The lathanides are mostly used in laser technology.

They deflect the I.R and U.V radiations and used in sun glasses.

The actinides series also consist of 14 elements with atomic number 90- 103.

All the elements have very similar properties.

All acitinides are radioactive.

All inner transition metals are placed at the bottom of periodic table.

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Answer:

IT IS A METALLOID..

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3 0
3 years ago
What is the melting point of a substance?
Alona [7]

Answer:

The answer is C) The temperature at which the solid-state turns into liquid

Explanation:

The melting point of a substance is the temperature at which it shifts state from solid to liquid. At the melting point, the solid and liquid levels exist in equilibrium. As heat is applied to a solid, its temperature will increase until the melting point is reached. More heat then will convert the solid into a liquid with no temperature change. This occurs when the internal energy of the solid increases, commonly by the application of heat or pressure, which increases the substance's temperature to the melting point.

6 0
3 years ago
Help me with all questions if you can!
Black_prince [1.1K]
31. B
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8 0
3 years ago
Read 2 more answers
We want to find how much charge is on the electrons in a nickel coin. follow this method. a nickel coin has a mass of about 5 g.
Lady bird [3.3K]
The mass of a nickel coin is 5 g.
1 mol of Ni weighs 58 g. 1 mol contains 6.022 x 10²³ atoms of Ni.
therefore in 58 g  there are 6.022 x 10²³ atoms of Ni
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3 0
3 years ago
I need help on this one for an exam real quick please​
gogolik [260]

Answer:

See Explanation

Explanation:

In the first case, when potassium iodide is added to an aqueous bromine solution, a chemical reaction occurs as follows;

Br2(l) + 2 KI(aq) = 2 KBr(aq) + I2(l)

This reaction produces iodine solution which is brown in colour.

Secondly, when potassium iodide is added to aqueous chlorine solution, the following reaction occurs;

2KI(aq) + Cl2(l)→ 2KCl(aq) + I2 (l)

This reaction also yields iodine solution which is brown in colour.

KI(aq) + I2(l) -------->K^+(aq) + I3^-(aq)

The  I3^-(aq) solution appears brown at high concentrations.

8 0
3 years ago
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