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1 year ago

State the type of bonding—ionic, covalent, or metallic—you would expect in each: (b) MgCl₂(s);

1 answer:

3 0

MgCl2 is an ionic compound because chemical bonds in the molecule are formed by the transfer of electrons among Mg and Cl atoms.

<h3>What is chemical bond ?</h3>

A chemical bond is a strong bond that can be formed between atoms, ions, or molecules to create chemical compounds. The bond may be created by the sharing of electrons in covalent bonds or by the electrostatic attraction of two oppositely charged ions, as in ionic bonds. Covalent, ionic, and metallic bindings are examples of "strong bonds" or "primary bonds," whereas dipole-dipole interactions, the London dispersion force, and hydrogen bonding are examples of "weak bonds" or "secondary bonds."

The positively charged protons in the nucleus and the negatively charged electrons in its orbit are attracted to one another by the basic electromagnetic force.

To learn more about chemical bonds from the given link:

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A chemist prepares a solution of copper) sulfate (cuso4)by weighing out 29.9 g of copper ) sulfate into a 150 into a 150.mLvolum

Alexxandr [17]

Lol Most people would say c but its A

6 0

2 years ago

Ground-state ionization energies of some one-electron species are

Troyanec [42]

The ionization energy of $B^{4+}$ is $3.28199 \cdot 10^{7} \mathrm{~J} / \mathrm{mol}$$$ .

<h3>What is ionization energy?</h3>

It is the energy needed to remove one electron from a neutral atom, which results in the formation of an ion.

The measurement is based on an isolated atom in its gaseous phase and is often expressed in kJ/mol.

b) Atom is ionized when the electron is completely removed from its electron cloud (so it being moved from first, $n_{\text {initial }}=1$ to the infinity's shell and $n_{\text {final }}=\infty$ ), and now the equation can be written as

$\Delta E=-2.18 \cdot 10^{-18} J\left(\frac{1}{n_{\text {final }}^{2}}-\frac{1}{n_{\text {initial }}^{2}}\right)\\=-2.18 \cdot 10^{-18} J\left(\frac{1}{\infty^{2}}-\frac{1}{1}\right)$

So the ionization energy is affected by the charge of the nucleus and the general formula can be represented as:

$\Delta E_{I E}=-2.18 \cdot 10^{-18} J\left(\frac{1}{\infty^{2}}-\frac{1}{1}\right) \cdot Z^{2} \cdot\left(6.022 \cdot 10^{23}\right molecules/mol)$ and as $\frac{1}{\infty}=0$

$\begin{gathered}\Delta E_{I E}=-2.18 \cdot 10^{-18} \mathrm{~J} \cdot Z^{2} \cdot\left(6.022 \cdot 10^{23} \text { molecules } / \mathrm{mol}\right) \\\Delta E_{I E}=1.312796 \cdot 10^{6} \mathrm{~J} / \mathrm{mol} \cdot Z^{2}\end{gathered}$

The $B^{4+}$ has an atomic number Z=5, therefore using the formula when $$n_{\text {initial }}$ =1, we get

$\Delta E_{I E}=1.312796 \cdot \mathrm{J} / \mathrm{mol} \cdot 5^{2}\\=3.28199 \cdot 10^{7} \mathrm{~J} / \mathrm{mol}$

The ionization energy of $B^{4+}$ is $3.28199 \cdot 10^{7} \mathrm{~J} / \mathrm{mol}$$$ .

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3 0

1 year ago

The solubility of calcium oxalate, CaC2O4, in pure water is 4.8 × 10‑5 moles per liter. Calculate the value of Ksp for silver c

inn [45]

Answer:

2.3 × 10⁻⁹

Explanation:

Step 1: Write the reaction for the solution of calcium oxalate

CaC₂O₄(s) ⇄ Ca²⁺(aq) + C₂O₄²⁻(aq)

Step 2: Make an ICE chart

We can relate the molar solubility (S) with the solubility product constant (Ksp) through an ICE chart.

CaC₂O₄(s) ⇄ Ca²⁺(aq) + C₂O₄²⁻(aq)

I 0 0

C +S +S

E S S

The solubility product constant is:

Ksp = [Ca²⁺] × [C₂O₄²⁻] = S² = (4.8 × 10⁻⁵)² = 2.3 × 10⁻⁹

4 0

3 years ago

The electronegativity of nitrogen (N) is 3.0, while the electronegativity of hydrogen (H) is 2.1. Knowing this, consider how the

Ede4ka [16]

Answer:

NH3 is polar due to the bonds between nitrogen and hydrogen which have different electronegativity and due also to its asymmetrical shape.

Explanation:

NH3 is polar as there are 3 dipoles in the ammonia molecule that do not balance each other out.

Considering the N-H bond which is polar because N with an electronegativy of 3.0, is more electronegative than H, with an electronegativity of 2.1. The is overall asymmetrical shape of NH3

means that the dipoles remains unbalanced and do cancel out each other making the NH3 polar.

4 0

3 years ago

Any one know the answer?

quester [9]

The last one, answer is D

8 0

3 years ago