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allochka39001 [22]

3 years ago

11

Please someone answer for this question

2 answers:

Gennadij [26K]3 years ago

5 0

Answer:

Hello...

Step-by-step explanation:

1st box-11,7

2nd box-5,3

3rd box-15

<u>HOPE</u><u> </u><u>IT</u><u> HELPS</u><u> YOU</u><u> </u><u>DEAR</u><u>.</u><u>.</u><u>.</u><u>.</u>

Maslowich3 years ago

3 0

First one is 5/3
Second one is: 5
Third one is: 15

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Im deleting my account and here is my points<br><br> Bye peeps

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Together, teammates Pedro and Ricky got 2673 base hits last season. Pedro had 275 more hits than Ricky. How many hits did each p

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Rickey got 1199 and Pedro got 1474. I got that by subtracting 275 from 2673 to get 2398. Than you divide 2398 to get 1199 which is Rickey's answer but to get Perdro you have to add 275 to get his answer of 1474.

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Can someone tell me what 2 to the power of 6 is

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Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

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