All categories

3 years ago

The maximum cost is $35. what is inequality. that's the question, i didn't write this

Mathematics

2 answers:

natulia [17]3 years ago

8 0

The answer to this is M ≤35

g100num [7]3 years ago

5 0

Answer:

well i would just use my stand power to answer this but nahhh you got it g

Step-by-step explanation:

You might be interested in

PLS HELP WITH THIS MATH

laiz [17]

I think it’s 28.35

54/100 x 5 = 2.7
54 + 2.7 = 56.7
56.7/100 x 50 = 28.35
56.7 -28.35 = 28.35

6 0

2 years ago

Read 2 more answers

What is the value of Tangent (t/2) if Cosine (t) = 4/5 and t is in quadrant IV?

mihalych1998 [28]

Answer:

-1/3

Step-by-step explanation:

Right on edge2020

8 0

3 years ago

Read 2 more answers

8 and 3/15 - 4 and 3/15

Iteru [2.4K]

Answer:

Step-by-step explanation:

8 3/15 - 4 3/15 the 3/15 cancel each other out so then there is only 8-4 which is 4

8 0

3 years ago

Read 2 more answers

The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate

soldi70 [24.7K]

Answer:

a) $V = 33510.322\,in^{3}$ , b) $A_{s} = 5026.548\,in^{2}$ , c) $\% V = 0.450\,\%$ , $\%A_{s} = 0.300\,\%$ .

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

$V = \frac{4}{3}\pi \cdot r^{3}$

$A_{s} = 4\pi \cdot r^{2}$

a) The volume of the sphere is:

$V = \frac{4}{3}\pi \cdot (20\,in)^{3}$

$V = 33510.322\,in^{3}$

b) The surface area of the sphere is:

$A_{s} = 4\pi \cdot (20\,in)^{2}$

$A_{s} = 5026.548\,in^{2}$

c) The total differentials for volume and surface area of the sphere are, respectively:

$\Delta V = 4\pi\cdot r^{2}\,\Delta r$

$\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)$

$\Delta V = 150.796\,in^{3}$

$\Delta A_{s} = 8\pi\cdot r \,\Delta r$

$\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)$

$\Delta A_{s} = 15.080\,in^{2}$

Relative errors are presented hereafter:

$\%V = \frac{\Delta V}{V}\times 100\%$

$\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%$

$\% V = 0.450\,\%$

$\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%$

$\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%$

$\%A_{s} = 0.300\,\%$

4 0

3 years ago

Thanks for the help number 11

jasenka [17]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers