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Lesechka [4]
2 years ago
12

20 points PLEASE HELP IT'S DUE TODAY

Mathematics
1 answer:
Afina-wow [57]2 years ago
5 0

Answer:

Step-by-step explanation:

Arc length of the circle is given by,

Arc length = \frac{\theta}{360^{\circ}}(2\pi r)

Area of the sector of a circle = \frac{\theta}{360^{\circ}}(2\pi r)

22). Arc length of the circle having central angle = \frac{\pi}{3}

                                                                                 = 60°

Arc length = \frac{60^{\circ}}{360^{\circ}}(2\pi )(7)

                 = \frac{14\pi }{6}

                 = 7.33 cm

23). Arc length of the circle having central angle = 225°

Arc length = \frac{225^{\circ}}{360^{\circ}}(2\pi )(10)

                 = 12.5π

                 = 39.27 km

24). Central angle = \frac{5\pi }{4}

                              = \frac{5\times 180^{\circ}}{4}

                              = 225°

Area of the sector = \frac{225^{\circ}}{360^{\circ}}(2\pi )(11)

                               = 43.20 yd²

25). Area of the sector = \frac{270^{\circ}}{360^{\circ}}(2\pi )(14)

                                      = 65.97 yd²

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lesya692 [45]

Answer:

first car = 35, second car= 15

Step-by-step explanation:

40x+15y=1625

x+y=50

multiplying the 2nd by -15 and add the 2 equations, we get x= 35 and by substituting on second equation we get y= 15

4 0
2 years ago
What is the area of triangle PQR? Round to the nearest tenth of a square unit.
larisa86 [58]
ANSWER

111.3 square units.

EXPLANATION

The formula for calculating the area of a triangle is.

Area = \frac{1}{2} \times base \times height
Let us the side of the triangle with side 12 units to be the base of the triangle.

Then the height of the triangle can be determined from the diagram using trigonometry.

\sin(68 \degree) = \frac{height}{20 }

height = 20 \sin(68 \degree)

height = 18.54

We now plug in the values in to the formula to obtain,

Area = \frac{1}{2} \times 12 \times 18.54

Area = 111.3 \: square \: units

See graph

7 0
3 years ago
Read 2 more answers
Which of the following is a solution of x^2+8x= -32
juin [17]

Answer:

X1=-4+4i

X2=-4-4i

Step-by-step explanation:

X^2+8x+32=0

Δ=b^2-4ac=8^2-4(32)=-64<0

X1=(-b-i√Δ) /2a=(-8-8i)/2=-4-4i

X2=(-b+i√Δ) /2a=(-8+8i)/2=-4+4i

3 0
2 years ago
the height of two is recorded after 1, 2, and 3 weeks as shown in the graph at the right. which plants' growth represents a prop
vagabundo [1.1K]
For the more amount of the time the larger it will grow.
6 0
3 years ago
Write one sine and one cosine equation for each graph below.
pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x  

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.  

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x  

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

6 0
2 years ago
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