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marishachu [46]

4 years ago

10

An object is in circular motion with a constant speed of 4 m/s with a radius of 4 m. what is the centripetal acceleration of the

object?

1 answer:

mina [271]4 years ago

3 0

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A 1.20x10^3 kilogram car is traveling east at 25 meters per second. the brakes are applied and the car is brought to rest in 5.0

lana [24]

Answer:

F = 7500 N

Explanation:

given,

mass of the car, m = 1200 Kg

initial speed of the car, v = 25 m/s

final speed of car = 0 m/s

time in which car is at rest, t = 5 s

distance = 50 m

Force = ?

using equation of motion for the calculation of acceleration.

v² = u² + 2 a s

0² = 25² + 2 x a x 50

100 a = -625

a = - 6.25 m/s²

negative sign shows deceleration of the car

now, force calculation

F = m a

F = 1200 x 6.25

F = 7500 N

hence, net force is equal to F = 7500 N

5 0

3 years ago

Beams of high-speed protons can be produced in "guns" using electric fields to accelerate the protons. A certain gun has an elec

Natasha2012 [34]

Answer: v = 2.75 * 10^7 m/s

Explanation: Since the electric field is a uniform one and the distance is small, the motion of the electron is of a constant acceleration, hence newton's laws of motion is applicable.

From the question

E=strength of electric field = 214N/c

q=magnitude of an electronic charge = 1.609* 10^-16c

m= mass of an electronic charge = 9.11*10^-31kg

v = velocity of electron.

S= distance covered = 1cm = 0.01m

a = acceleration of electron.

F = ma but F=Eq

Eq = ma.

a = Eq/m

a = 214 * 1.609*10^-16/ 9.11 * 10^-31

a = 344.32 * 10^-16/ 9.11 * 10 ^-31

a = 3. 779* 10^16 m/s²

Before the electron is accelerated, they are always not moving, hence initial velocity (u) = 0.

By using the equation of motion, we have

v² = u² + 2aS

But u = 0

v² = 2aS

v²= 2* 3.779*10^16 * 0.01

v² = 7.558 * 10^14

v = √7.558 * 10^14

v = 2.75 * 10^7 m/s.

6 0

3 years ago

How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of ele

konstantin123 [22]

Answer:

-1486 KJ

Explanation:

The work done by an electric field on a charged body is:

W = ΔV * q

where ΔV = change in voltage

q = total charge

The total charge of Avogadro's number of electrons is:

6.0221409 * 10^(23) * -1.6023 * 10^(-19) = -9.65 * 10^(4)

The change in voltage, ΔV, is:

9.20 - (6.90) = 15.4

Therefore, the work done is:

W = -9.65 * 10^(4) * 15.4 = -1.486 * 10^6 J = -1486 KJ

The negative sign means that the motion of the electrons is opposite the electrostatic force.

5 0

3 years ago

A projectile is launched at ground level with an initial speed of 50.0 m/s at an angle of 30.0Â° above the horizontal. it strike

Anni [7]

<span>x = 129.9 m y = 30.9 m First, let's calculate the horizontal and vertical velocities involved h = 50.0cos(30) = 43.30127 m/s v = 50.0sin(30) = 25 m/s The horizontal distance is simply the horizontal velocity multiplied by the time, so 43.30127 m/s * 3 s = 129.9 m So the horizontal distance traveled is 129.9 m, so x = 129.9 m The vertical distance needs to take into account gravity which provides an acceleration of -9.8 m/s^2, so we get d = 25 m/s * 3s - 0.5*9.8 m/s^2 * (3 s)^2 d = 75 m - 4.9 m/s^2 * 9 s^2 d = 75 m - 44.1 m d = 30.9 m So the vertical distance traveled is 30.9 m, so y = 30.9 m</span>

8 0

4 years ago

A large box sits on a rough floor. A person pushes on the box with a horizontal force of magnitude 50 N. The box remains at rest

artcher [175]

Answer:

The magnitude of the frictional force is $F_f \ge 50 \ N$

Explanation:

From the question we are told that

The force exerted on the box is $F = 50 \ N$

Generally for the box to remain at rest then it means that the frictional force is greater than or equal to the force applied to move it i.e

$F_f \ge F$

=> $F_f \ge 50 \ N$

5 0

3 years ago