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3 years ago

Explain what happens when particles collide

Physics

1 answer:

Tanya [424]3 years ago

3 0

Answer

they transfer energy

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A CO molecule has an intrinsic dipole moment whose magnitude is 4 X 10^-31 C*m. If the separation between the atoms is 0.11 nm,

aleksandrvk [35]

4x10^-31/(0.11x10^-9)= 3,63 x 10^-21

5 0

3 years ago

A car of mass 1500 kg travels due East with a constant speed of 25.0 m/s. Eventually it turns right, and travels due South with

e-lub [12.9K]

Answer:

The direction of the car’s change in linear momentum is 149.04° West of North

Explanation:

Momentum is defined as the product of mass of a body and its velocity

Momentum = mass × velocity

Change in Momentum = mass × change in velocity

∆P = m∆v

∆P = m(v-u)

Given m = 1500kg

v = 25m/s

u = 15m/s

∆P = 1500(25-15)

∆P = 1500×10

∆P = 15,000kgm/s

Since the car first travels due East i.e +x direction

x = 25m/s

Travelling due south is negative y direction

y = -15m/s

Direction of the car change

θ = tan^-1(y/x)

θ = tan^-1(-15/25)

θ = tan^-1(-0.6)

θ = -30.96°

Since tan is negative in the second quadrant

θ = 180-30.96

θ = 149.04°

The direction of the car’s change in linear momentum is 149.04° West of North

5 0

4 years ago

Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.23 2.23 times a second. A tack is stuck in the t

elena-14-01-66 [18.8K]

Explanation:

The given data is as follows.

Angular velocity ( $\omega$ ) = 2.23 rps

Distance from the center (R) = 0.379 m

First, we will convert revolutions per second into radian per second as follows.

= 2.23 revolutions per second

= $2.23 \times 2 \times 3.14 rad/s$

= 14.01 rad/s

Now, tangential speed will be calculated as follows.

Tangential speed, v = $R \times \omega$

= 0.379 x 14.01

= 5.31 m/s

Thus, we can conclude that the tack's tangential speed is 5.31 m/s.

8 0

3 years ago

30 minus 3 plus 4 is equal to what

Pepsi [2]

Answer:

Explanation:

quick maths

6 0

3 years ago

Read 2 more answers

A current of 2.35 A flows through a 1.11 mm diameter copper wire that is connected to a capacitor plate. The current is directed

antoniya [11.8K]

Answer:

charge flowing in the copper wire is $2.585\times 10^{-3}C$

Explanation:

We have given current i = 2.35 A

Time through which charge is charge is transferred $t=1.10\times 10^{-3}sec$

We have to find the charge flowing in this time

We know that charge is given by Q = i×t , here i is current and t is time

So charge = $Q=1.1\times 10^{-3}\times 2.35=2.585\times 10^{-3}C$

So charge flowing in the copper wire is $2.585\times 10^{-3}C$

6 0

4 years ago