Answer:
43.83 nC
Explanation:
We know Q = ε₀Ψ where Q = charge enclosed by the cubic box, ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m and Ψ = net electric flux through cubic box = 4950 Nm²/C
So, substituting the values of the variables into the equation, we have
Q = ε₀Ψ
= 8.854 × 10⁻¹² F/m × 4950 Nm²/C
= 43827.3 × 10⁻¹² C = 4.38273 × 10⁻⁸ C
= 43.8273 × 10⁻⁹ C
= 43.8273 nC
≅ 43.83 nC
The loops must the coil have to generate a maximum emf of 2500 will be 439.
<h3 /><h3>What is the faraday law of electromagnetic induction?</h3>
According to Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the flow of amount of current.
Given data;
Area,A = 0.239 m²
Angular velocity,ω=373 rad/sec
Magnetic field,B=0.0639 T
Maximum emf,E= 2500V
The formula for the maximum induced voltage is;
E{max} = N × B × A × ω
2500 = N × 0.639 × 0.0239 × 373
N = 438.66
N = 439 \ turns
Hence, loops must the coil have to generate a maximum emf of 2500 will be 439.
To learn more about the faraday law of electromagnetic induction refer to;
brainly.com/question/26334813
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