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Yakvenalex [24]
3 years ago
7

How to do exponential functions

Mathematics
1 answer:
bogdanovich [222]3 years ago
6 0
In an exponential function, the independent variable, or x-value, is the exponent, while the base is a constant. For example, y = 2^x would be an exponential function. Here's what that looks like. The formula for an exponential function is y = ab^x, where a and b are constants.

If you need more information go to this website:

<span>study.com/academy/lesson/what-is-an-exponential-function.html</span>
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Chad used the table to show the ratios of the different types of sports game cards that he owns. For every 2 offense cards, he o
Travka [436]

Answer:

The graph that has the points (2,4) and (4,8) should be the answer.

Step-by-step explanation:

This is the answer because if you see the ratio 2:4, that means that for every 2 offense cards there are 4 defense cards. As you continue to go up it would be (4,8), (6,12), (8,16), and so forth.

3 0
3 years ago
Read 2 more answers
Alice was having a conversation
Akimi4 [234]
What's the question..???
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3 years ago
(4.8x10x7) + 6,500,000 what is the value of the expression
Fiesta28 [93]

Answer:

=(48*7) +65*10^5

=((40+8) *7) +65*10^5

=(280+56)+65*10^5

=336+65*10^5

=.336*10^3+65*10^5

=.00336*10^5+65*10^5

=(.00336+65) *10^5

=64.00336*10^5

4 0
3 years ago
Find the sum of the series and show your process for finding each term leading to the final sum.
Crazy boy [7]

ANSWER

\sum_{k=3}^5( - 2k + 5) =  - 9

EXPLANATION

The given series is

\sum_{k=3}^5( - 2k + 5)

This series is finite.

The expanded form is

\sum_{k=3}^5( - 2k + 5) = ( - 2 \times 3 + 5) + ( - 2 \times 4 + 5) + ( - 2 \times 5 + 5)

This simplifies to

\sum_{k=3}^5( - 2k + 5) = ( - 6 + 5) + ( - 8+ 5) + ( - 10+ 5)

\sum_{k=3}^5( - 2k + 5) = ( - 1) + ( - 3) + ( - 5)

\sum_{k=3}^5( - 2k + 5) =  - 9

5 0
3 years ago
A circular garden has a circumference of
omeli [17]

This solution to this problem is predicated on the fact that the circumference is just: 2\pir. A straight line going through the center of the garden would actually be the diameter, which is well known to be two times the radius of the circle, so we can say that the circumference is just:

d\pi

So, solving for both the radius and the diameter gives us:

d\pi=8xy^2\pi\\ d=8xy^2\\ \\ 2\pi r=8xy^2\pi\\ r=4xy^2

So, the length of thes traight path that goes through the center of the guardain is just 8xy^2, and we can use the radius for the next part of the problem.

The area of a circle is \pi r^2, which means we can just plug in the radius and find our area:

A=\pi r^2 \implies \\ A=\pi (4xy^2)^2\implies \\ A= 16\pi x^2y^4

So, we have found our area(16 \pi x^2 y^4) and the problem is done.

6 0
3 years ago
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