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Anika [276]
3 years ago
15

What is $3.99 rounded to the nearest penny

Mathematics
2 answers:
Misha Larkins [42]3 years ago
8 0
$3.99 rounded to the nearest penny would be $4.00
geniusboy [140]3 years ago
5 0
 i believe its $ 4.00

hope i helped
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How do i do this please help
Aleks04 [339]
-5x+2>37
Subtract two from both sides
-5x>35
Then divide five
X<-7
You have to flip the sign when you divide with a negative.
3 0
3 years ago
Read 2 more answers
A map has a scale of 1:200000 How far is it from Belfast to Larne in Km if the distance on the map is 7.8cm
vivado [14]

Answer:

15.6km

Step-by-step explanation:

Given the map scale 1:200000

1cm on the map represents 200000 cm on ground or in actual distance

Hence, if distance from Belfast to Larne is 7.8vm on map ;

Actual distance will be :

7.8 * 200000 = 1560000 cm

Converting to km :

Recall :

1000 m = 1km

100 cm = 1 m

Hence,

100000 cm = 1km

Therefore, (1560000 / 100000) km

= 15.6km

Hence, distance between Belfast and Larne is 15.6km

6 0
3 years ago
25a-3b+7a+25b-18a-16b+20b
GrogVix [38]
The answer to ur question is 19a+b
8 0
3 years ago
Find the value of x.
Tresset [83]

Answer:

x = 26

Step-by-step explanation:

If angle a and b are congruent, then set 68 and 4x + 8 together to equal to 180 on the right side.  Combine 68 and 8 together to get 76.  Then, subtract 76 on both sides to get 104 on the right side.  Divide that number by 4 to get your x-value which is 26.

6 0
4 years ago
A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 meter per second, while the cat
LenKa [72]

Answer:

They'll meet after 200 meters , if they simultaneously start running towards each other.

Step-by-step explanation:

Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.

Dog: Distance =Speed x time: x=30t

Cat: Distance = 200-x

=24t

The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs

So they will meet after 3.7 seconds

To check:

Distance travelled by dog :x=30(3.7)

=111.11 meters

Distance travelled by cat: 24t=24(3.7)

=88.89 meters

Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89

=200 meters

6 0
2 years ago
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