Answer:
7/16
Approximately 0.44
Step by step explanation:
For the 1st student to arrive before 2nd student,
* the probability that he(1st student)to arrive during 3/4 hrs = 3/4
*Then he(1st student) will need to wait for 1/4 hrs
*The probability that he(1st student) arrive during the last 1/4 hrs = 1/4
*Then he(1st student) waits for average of 1/8 hrs (1/4 + 1/4)=1/8
*The total time he(1st student) wait = (3/4 ×1/4) +(1/4× 1/8) = 7/32
*For 1st and 2nd student to meet, the 2nd student need to arrive when 1st student is still arround, therefore the probability that 2nd student arrives when 1st student is arround = 7/32
*If 2nd student arrives before 1st student, the probability that they would meet is 7/32
* Adding both together 7/32 + 7/32 = 7/16
ANSWER = 0.4375
=0.44
-24 and 3 multiply to -72 and add up to -21
Answer:
-3 times the square root of 5
=============================================
Explanation:
Let
Replace all the root 5 terms with x and we go from
to
From here, combine like terms to get
and the last thing to do is replace the x with sqrt(5)
Meaning that,
<h2>
<em>Answer:</em></h2><h2>
<em>Option </em><em>A</em></h2>
<em>Linear</em><em> </em><em>increasing</em>
<em>Additional</em><em> Information</em><em>:</em>
<em>Linear </em><em>functions </em><em>are </em><em>those </em><em>whose </em><em>graph </em><em>is </em><em>a </em><em>straight</em><em> </em><em>line.A </em><em>linear </em><em>function </em><em>has </em><em>the </em><em>following</em><em> </em><em>form:</em>
<em>y=</em><em>m</em><em>x+</em><em>b</em>
<em>m=</em><em>slope</em>
<em>b=</em><em>y- </em><em>intercept</em>
<em>A </em><em>linear </em><em>function </em><em>has </em><em>one </em><em>independent</em><em> </em><em>variable </em><em>and </em><em>dependent </em><em>variable.The </em><em>independent</em><em> </em><em>variable </em><em>is </em><em>X </em><em>and </em><em>dependent</em><em> </em><em>variable</em><em> </em><em>is </em><em>y.</em>
<em>Initial </em><em>values </em><em>are </em><em>called </em><em>y-intercept.</em>