We are given the function <span>f(x) = 3^x+1 - 2 and is asked for the asymptote and y-intercept. In this case, we transform the function to
y +2 = 1/3^(x+1)-1
y = 1-2</span>/3^(x+1)-1/(3^(x+1)-1)
let 3^(x+1)-1 = 0
<span>1/3^(x+1) = 0
x = infinity
when x = infinity
y = 0 - 2
y = -2
The y-intercept is the value where x = 0. substituting,
y = 3^(0+1) - 2 = 1 </span>
Answer:
Step-by-step explanation:
d=80 ft
r=80/2=40 ft
volume of cylinder=π r²h,where h is height or depth of cylinder.
π×40²×h=825,000
πh=825,000/40²=4125/8
h=4125/(8π)≈164.1285≈164.13 ft
Both positive, so quadrant I
The scale factor is 2 so you would increase each length by 2
The sum of 14 and 3 is equal to 17