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Zielflug [23.3K]
3 years ago
11

Write the following expression in exponential form: 3x3x3x3x3x3

Mathematics
2 answers:
mr_godi [17]3 years ago
6 0
3^6 
or 
729  because 3 time 3 times 3 times 3 time 3 times 3 is 729

Likurg_2 [28]3 years ago
5 0
3*3*3*3*3*3.  What would come to your mind is: How many 3s are there? So they are six. Which is equal to 3 ^{6}. = 729.
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What is 8 raised to the -2/3 power? I need help
Naddik [55]

Answer:

The answer will be 0.25 or 1/4

Step-by-step explanation:

8^(-2/3)= 0.25

HOPE THIS HELPS!! PLEASE GIVE BRAINIEST!!

7 0
3 years ago
Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -
rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by  D and its formula is

D=b^2-4ac\\

Where

a= the coefficient of the x^{2}

b= the coefficient of x

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant  and evaluate our answer accordingly .

Let us start with

y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\

Hence we have two real roots for this equation.

y = 2x^2 - 6x + 5\\

y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D

Hence we do not have any real root for this quadratic

y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\

Hence D>0 and thus we have two real roots for this equation.

y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\

Hence we have one real root to this quadratic equation.

7 0
3 years ago
What does it mean when there are variables on top of each other in parentheses in statistics?
Ilya [14]
It's a combination:
\left(  {{n} \atop {k}}\right)\equiv C(n,k)=\dfrac{n!}{(n-k)!k!}
4 0
3 years ago
Which of the following is the sum of the slopes of the line 3x+y=1 and a line perpendicular to this line? A 0 B 13 C −83 D −6
laiz [17]

Answer:

-8/3

Step-by-step explanation:

First find the slope of the line

3x+y = 1

Solve for y

y = -3x+1

This is in slope intercept form

y = mx+b where m is the slope

The slope is -3

The slopes of perpendicular lines multiply to -1

m* -3 = -1

m = 1/3

The line perpendicular has a slope of 1 / (3) = 1/3

The sum is -3 + 1/3

-9/2 + 1/3 = -8/3

3 0
4 years ago
Kdkvnsdfkfvqmehgrhgtevnm,vjwgqv
soldier1979 [14.2K]

Answer:

I don't know I can't understand do you know that you will lose 5 points

8 0
4 years ago
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