An 18 fluid ounce bottle of lotion costs $10.99, what is the price per fluid ounce?

Find the arc length s, of an arc with central angle θ=210∘ and radius r=5cm.

olga_2 [115]

The relationship between radius (r), angle (θ), and arc length (s) is given by
.. s = r*θ . . . . . . . . θ in radians
.. s = (5 cm)*(210π/180)
.. s = 35π/6 cm
.. s ≈ 18.33 cm

3 0

3 years ago

5% of 120 20% of 36 75% of 680 35% of 480

BlackZzzverrR [31]

The answer is B and put the question next time

6 0

3 years ago

Morgan uses 1/4 of her supply of raisins to make trail mix and 3/8 of her supply of raisins to make cookies. If Morgan uses 5 po

Mnenie [13.5K]

First, we have to find how much supply of raisins she uses. It is 1/4+3/8=5/8. It makes the total 5 pounds of raisins that she uses. Constructing an equation, we can find how much raisins are available in her supply. $\frac{5}{8} x = 5$ . And the x= 8.

5 0

3 years ago

The function f(h)=m(1/2)^h gives the mass, m, of a radioactive substance remaining after h half-lives. Cobalt-60 has a half-life

goldfiish [28.3K]

Answer:

Third choice:

$f(x)=50(0.877)^{10};13.5mg$

Explanation:

1. Data:

Function:

$f(h)=m(1/2)^h$

Cobalt-60's half-life: 5.3 years

Initial mass of cobalt-60: 50 mg

2. Unknown:

equation for the mass of cobalt-60 remaining after 10 years = ?

mass remaining =?

3. Solution

Half-life is the time it takes a sample to decay to half of its initial amount. It is considered constant. Hence, when one half-life passes, the sample has decayed to 50% of the original amount; when two half-lives pass, the sample has decayed to (1/2)×(1/2) = 1/4 = 25%; when three half-lives have elapsed, the sample has decayed to (1/2)³ = 1/8 = 12.5% of its original amount, and so on.

Then, the amound of a sample remaining is calculated as the original amount times (1/2) raised to the number of half-lives elapsed, which is what the given function, $f(h)=m(1/2)^h$ models.

You just must substitute the data into the function to get the answer to the question:

$f(x)=50(0.5)^{(10/5.3)}$

Where, 50 is the original mass of 50g, 0.5 is equal to 1/2, and 10/5.3 gives the number of half-lives (the number of times that 5.3 years is contained in 10 years).

Simplifying:

$f(x)=50(0.5)^{(10/5.3)}=50((0.5)^{(1/5.3})^{10}\approx50(0.877)^{10}$