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harina [27]
2 years ago
8

√(4/7)^2 = equations with square roots and cube roots

Mathematics
2 answers:
finlep [7]2 years ago
4 0
The answer is : 4/7
Decimal: 0.571 (Not Rounded)
zhenek [66]2 years ago
3 0

Answer:

See below

Step-by-step explanation:

If you are squaring a number, and then taking the square root of it, you are essentially undoing the original operation:

\displaystyle \sqrt{\biggr(\frac{4}{7}\biggr)^2}=\biggr[\biggr(\frac{4}{7}\biggr)^2\biggr]^{\frac{1}{2}}=\biggr(\frac{4}{7}\biggr)^{2*\frac{1}{2}}=\frac{4}{7}

Hence, we are back starting with the original number

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The diagonals of a rumbus are 21m and 32m what is area of the rombus
Liula [17]
Consider this option:
1. formula is: S=0.5*d₁*d₂, where d₁;d₂ - the diagonals of the rhombus.
2. substituting the values into the formula: S=0.5*21*32=336 m².

answer: 336 m².
5 0
3 years ago
Read 2 more answers
There are 27 students in a class. 13 are
Feliz [49]

Answer: Seniors: 13/27 Juniors:14/27

Step-by-step explanation:

4 0
3 years ago
1.
bulgar [2K]

Answer:

8/9 will be left over

Step-by-step explanation:

3 7/9 + 5 1/3= 9 1/9

Now subtract the amount of paint needed by how much paint there is:

10- 9 1/9= 8/9

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Hope this helps

5 0
2 years ago
Someone plz help me with this
Phoenix [80]

Answer:

5y^{6}\sqrt{2}

Step-by-step explanation:

We want to  simplify:

\sqrt{50y^{12}}

We rewrite as:

\sqrt{2\times25 \times (y^{6})^2}

We split the radical sign to obtain:

\sqrt{25} \times \sqrt{(y^{6})^2} \times \sqrt{2}

Simplify the square root for the perfect squares to get:

5y^{6}\sqrt{2}

Therefore the simplified form is: 5y^{6}\sqrt{2}

8 0
3 years ago
Plz answer all corectly will mark brainlest plz answer within 1 hour
denis23 [38]

Answer:

for the first one I got y=-2x-2 the second part i got y=-x-1 or -1x-y-1=0  Correct me if I am wrong

Step-by-step explanation:

Use the slope formula

-4-4 =-8

  /               =-2

1 - -3=4

2. The second part use this formula y-y1=m(x-x1)

     y--4=-1(x-3)

y+4=-x+3

  -4      -4

y+0=-x-1

 y=-x-1      or -1x-y-1=0    I am not sure  

6 0
3 years ago
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