5k²-8k-45k+72 = 5k²-53k+72
Answer: 5k² - 53k + 72
Answer:
25
Step-by-step explanation:
5 times 5
Answer:
It produced 3797.5 tons before.
22.5% of 4900 is 1102.5
That subtracted from 4900 is 3797.5 tons
Answer:
Jamie
E = 35H
Michael
E = 4,500M
Step-by-step explanation:
Jamie's job paid her $35 an hour, while Michael's job had a $4,300 monthly salary.
Where,
E = Money earned
H = hours worked
M = months worked
Jamie
E = 35H
Where,
E = Total Amount earned
35 = amount earned per hour
H = Number of hours
** There is a mistake in the figures you gave for Michael. There are two different figures but I will go with 4,500
Michael
E = 4,500M
Where,
E = Total amount earned
4,500 = amount earned per month
M = Number of months
If Jamie made $20 an hour,
E = 20H
Let H = 1
E = 20(1)
= $20
When Jamie made $35 an hour
Assume H = 1
E = 35H
E = 35 × 1
= $35
Therefore, if Jamie made $20 an hour, her total money earned
will decrease
This is because, the higher the amount earned per hour, the higher the total amount Jamie will earn
Answer:
1)
The point estimate for the proportion of college graduates among women who work at home is 0.327
2)
The 80% confidence interval is given by (0.315; 0.339)
Step-by-step explanation:
For this case we have the following info given:
represent the women who worked at home who were college graduates
the sample size selected
Part 1
In order to find the proportion of college graduates among women who work at home and we can use the following formula:

The point estimate for the proportion of college graduates among women who work at home is 0.327
Part 2
Construct an 80% confidence interval for the proportion of women who work at home who are college graduates. Round the answer to three decimal places. An 80% confidence interval for the proportion of women who work at home Is < p <
The confidence interval for the true proportion would be given by this formula
For the 80% confidence interval the value for the significance is
and
, the critical value would be given by:
And replacing we goot:
The 80% confidence interval is given by (0.315; 0.339)