= 12/3 -5*12+4(12-2) = 4-60+40 = -16, so a
Answer:
10
Explanation:
The distance between two points of coordinates (x1, y1) and (x2, y2) can be calculated as:
![\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
So, the distance between (-2, 5) and (8, 5) is equal to:
![\begin{gathered} \sqrt[]{(8-(-2))^2+(5-5)^2} \\ \sqrt[]{(8+2)^2+(0_{})^2} \\ \sqrt[]{(10)^2+0} \\ \sqrt[]{100} \\ 10 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csqrt%5B%5D%7B%288-%28-2%29%29%5E2%2B%285-5%29%5E2%7D%20%5C%5C%20%5Csqrt%5B%5D%7B%288%2B2%29%5E2%2B%280_%7B%7D%29%5E2%7D%20%5C%5C%20%5Csqrt%5B%5D%7B%2810%29%5E2%2B0%7D%20%5C%5C%20%5Csqrt%5B%5D%7B100%7D%20%5C%5C%2010%20%5Cend%7Bgathered%7D)
Then, the distance between (-2, 5) and (8, 5) is 10.
Answer:
(2 , 5)
Step-by-step explanation:
point (x,y) that divides the segment PI in the ratio 2 to 1
PD=4 - (-2) = 6 PE/ED=2/1 PE=2ED PE+ED=6 3ED=6 ED=2 PE=4
coordinate of E (2,1) .... 2 is x coordinate of E
DI=7-1=6 DF/FI=2/1 DF=4
coordinate of F (4,5) .... .... 5 is y coordinate of E
CF // PD PC/CI=DF/FI=2/1
C (2,5)
5^-3 is 1/125
The negative in the exponent makes it so there is a 1 over the problem if there was no negative. When you have a negative in the exponent, the answer will be the reciprocal (opposite) of the question with no negative.
For example,
9^2 = 81
9^-2 = 1/81
Answer:
y-intercept = (0,
).
Step-by-step explanation:
Given the linear equation in standard form, 12x + 13y = 8:
We must transform this equation into slope-intercept form to make it easier to determine the coordinates of the y-intercept.
12x + 13y = 8
Subtract 12x from both sides:
12x + 13y - 12x = - 12x + 8
13y = - 12x + 8
Next, divide both sides of the equation by 13 to solve for y:

or 
Next, to determine the y-intercept, we must set x = 0 (because the y-intercept is the point where the graph of the linear equation crosses the y-axis).
Let x = 0:


Therefore, the value of y when x = 0 is
. This is the y-intercept, and its coordinate is (0,
).