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Evgen [1.6K]
3 years ago
7

Which characteristics are typical of a human population in the postindustrial stage?

Biology
2 answers:
Shkiper50 [21]3 years ago
6 0

Answer:

  • <u>Post-Industrial stage: </u>

During the post-industrial stage, the human population experienced a high birth rate, as there were more secure procedures and there were more medical facilities for the patients.

Explanation:

  • <u>High Birth rate:</u>

Research work was performed in doing safe new born deliver, along with that more advance instruments were developed creating it more easy for any doctor or nurse to apply the procedures easily. As, before there was lack of procedures and there were less advance instruments in order to carry out the whole process of delivery.

  • <u>Innovation of new and effective medicines:</u>

As there were research works carried out by medical personnel to improve the effectiveness of medicines, which eventually resulted in cure for more diseases. As there were less number of deaths caused due to illness or any disorder inside the human body.

  • <u>Increase rate of literacy:</u>

There was increase in the literacy rate in the different regions around the globe. As now there were many institution and schools that was offering quality education to the masses.

  • <u>More places to live safe and with convenience:</u>

There were more places for the people around the globe to live, as there were strong structures been built in the shape of buildings and then after that it went on to increase the level of convenience for people to live safely.

Furkat [3]3 years ago
3 0

The correct answer is emerging adulthood.

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Which observation best explains how the landform in the image was created ! PLEASE HELP !!!!!!!
Maksim231197 [3]

Answer:

dreams have been formed through the process of erosion

Explanation:

because it looks like little water streams cutting through the rock so it must have been eroded

5 0
3 years ago
Determine the phenotypic ratios of the offspring. 9 yellow-inflated : 3 yellow-constricted : 3 green-inflated: 1 green-constrict
skad [1K]

From a cross between dihybrid individuals, whose diallelic genes code for one trait each, expressing complete dominance, the phenotypic ratio is B) <em>9 green-inflated : 3 green-constricted : 3 yellow-inflated :1 yellow-constricted.</em>

-------------------------------

<em />

<em>Since I do not have the cross, I will assume the cross involves two dihybrid individuals by looking at the options.</em>

So, let us picture the situation,

  • Two diallelic genes code for one trait each, color and inflated/constricted pods.
  • G allele is the dominant and codes for green pods
  • g allele is recessive and codes for yellow pods
  • I is the dominant allele and codes for inflated pods
  • i is recessive and codes for constricted pods
  • These genes are not linked

1st Cross)   Two h0m0zyg0us individuals

Parental)  GGII     x     ggii

F1) 100% GgIi

2nd Cross) Selfcross between F1 individuals

Parentals)   GgIi    x    GgIi

Gametes) GI, Gi, gI, gi

                GI, Gi, gI, gi

Punnett square)     GI        Gi        gI       gi

                     GI      GGII     GGIi   GgII   GgIi

                     Gi      GGIi      GGii   GgIi   Ggii

                      gI      GgII     GgIi    ggII    ggIi

                      gi      GgIi     Ggii    ggIi     ggii

F2)    Genotype

  • 1/16 GGII
  • 2/16 GGIi
  • 1/16 GGii
  • 2/16 GgII
  • 4/16 GgIi
  • 2/16 Ggii
  • 1/16 ggII
  • 2/16 ggIi
  • 1/16 ggii

   

       Phenotype

  • 9/16 G-I- ⇒ Green and Inflated
  • 3/16 G-ii ⇒ Green and constricted
  • 3/16 ggI- ⇒ Yellow and inflated
  • 1/16 ggii ⇒ Yellow and constricted

Phenotypic ratio 9:3:3:1

<u>Options</u>

<u />

A) 9 yellow-inflated : 3 yellow-constricted : 3 green-inflated: 1 green-constricted ⇒ NOT CORRECT

B) 9 green-inflated : 3 green-constricted : 3 yellow-inflated : 1 yellow-constricted ⇒ <u>CORRECT</u>

C) 9 green-constricted : 3 green-inflated : 3 yellow-constricted : 1 yellow-inflated ⇒ NOT CORRECT

D) 9 yellow-constricted : 3 yellow-inflated : 3 green-constricted : 1 green-inflated ⇒ NOT CORRECT            

-----------------------------

Related link:  brainly.com/question/1185199?referrer=searchResults

                       brainly.com/question/12541734?referrer=searchResults

5 0
3 years ago
The four types of macromolecules in cells are nucleic_________<br> lipids, proteins, and_____
brilliants [131]

The four types of macromolecules in cells are nucleic acids, lipids, proteins, and carbohydrates.

8 0
3 years ago
Read 2 more answers
When a mitochondrial chaperone helps a mitochondrial matrix protein into the matrix by biased diffusion, the chaperone is said t
Elis [28]

Answer:

c. Brownian ratchet

Explanation:

Mitochondria are cell organelles. They are known as the power house of the cells. The energy needed to power the cell is generated by the mitochondria. They functions like a digestive system.

The mitochondria chaperone are proteins that helps the proteins along pathways for their folding. They shield the proteins from other proteins and protect them from binding the folding process. The chaperone are mainly concern with the folding of protein.

The chaperone acts as a Brownian ratchet as the mitochondrial chaperone guides the matrix protein into matrix by the biased diffusion process.

4 0
3 years ago
A female rabbit heterozygous at two genes (named A and B) is test-crossed with a male rabbit. Their progeny include 442 A/a;B/b,
natta225 [31]

Answer:

The genes are linked and 10 mu apart.

Explanation:

A female AaBb rabbit is test crossed with a male rabbit (aabb). The male can only produce<em> ab</em> gametes (all the progeny will have ab on one of the homologous chromosomes).

If the genes assorted independently, the female would produce 4 types of gametes with the same frequency: 1/4 AB, 1/4 Ab, 1/4 aB and 1/4 ab.

However, the observed AB and ab gametes were much more frequent than Ab and aB, which means that the genes are linked and alleles on the same chromosome do not assort independently during meiosis.

Recombination is a rare event, so the most abundant gametes are the parentals. That is how we know that the mother had the AB/ab genotype. The recombinant gametes therefore are Ab and aB.

Distance (mu) = # Recombinants × 100/ Total progeny

Distance = (54 + 46) × 100/ 1000

Distance =  100 × 100/1000

Distance = 10 mu

6 0
4 years ago
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