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3 years ago

Which of the following statements about soil formation is true?

Biology

2 answers:

cricket20 [7]3 years ago

8 0

Answer: B. Precipitation affects the rate at which nutrients are removed from soil.

Explanation:

Soil is an aggregate of minerals, gases, water, and organic matter which supports the life of the plants. The soil is formed by the weathering of the rocks. But the formation and development of soil depends upon factors like temperature of the surrounding environment, rainfall and plants growing on it. The rainfall or precipitation can directly influence the quality of the soil. Too much rainfall can lead to leaching or removal of the inorganic and organic nutrients from the soil. They may make the soil acidic.

Kisachek [45]3 years ago

6 0

B. Precipitation affects the rate at which nutrients are removed from soil.

Soil is known to be a loose mixture of rock fragments, water, organic materials and air that usually accommodate the growth of vegetation. Thus, formation and development of soil is a dynamic process rather than static and soil is present when pre-historic animals roamed the Earth and some these animals are preserved only fossilized soils buried deep beneath our present soil.

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Two different enzymes catalyze the same reaction and both exhibit the same Vmax. When Enzyme A was run with a 40 uM substrate, t

Vinil7 [7]

Answer:

a) k_m = 4.08 uM

V_{max} = 20.07 uM/min

b) k_m = 8.16 uM

Explanation:

Given that:

For Enzyme A:

the substrate concentration [S] = 40 uM

the initial velocity rate v = 10 uM/min

when it was 4mM, v = 20 uM/min

i.e.

at 4mM = 4000 uM;

Using Michealis -menten equation;

when v = 10

$V = \dfrac{V_{max}[S]}{k_m+[S]}$

∴

$10 = \dfrac{V_{max}\times 40}{k_m + 40}$

$10 (k_m + 40) = V_{max}40$

$40V_{max} -10k_m = 400 --- (1)$

when v= 20

$20= \dfrac{V_{max}\times 4000}{k_m + 4000}$

$20 (k_m + 4000) = V_{max}4000$

$4000V_{max} -20k_m = 8000 --- (2)$

equating equation (1) and (2):

$40V_{max} -10k_m = 400 --- (1)$

$4000V_{max} -20k_m = 8000 --- (2)$

let multiply equation (1) by 100 and equation (2) by 1

4000V_{max} - 1000K_m = 4000

0 -980k_m = 4000

k_m = 4000/-980

k_m = 4.08 uM

replacing the value of k_m into equation (1)

40{V_max } - 10(4.08) = 400

40{V_max } - 40.8 = 400

40{V_max } = 400 + 40.8

40{V_max } = 440.8

V_{max} = 440.8/40

V_{max} = 11.02 uM/min

Since V_{max} of A ie equivalent to that of B; then:

V_{max} of B = 11.02 uM/min

Here;

[S] = 80 uM

V = 10 uM/min

∴

$10 = \dfrac{11.02 \times 80}{k_m + 80 }$

10(k_m +80) = 881.6

10k_m = 881.6 - 800

10k_m = 81.6

k_m = 81.6/10

k_m = 8.16 uM

8 0

3 years ago