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alexandr402 [8]
3 years ago
7

How to find the volume and total surface area for a triangular prism​

Mathematics
1 answer:
Neko [114]3 years ago
3 0

Answer:

Step-by-step explanation:

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Choose the correct definition of a sampling distribution. The sampling distribution of a statistic of size isa.the distribution
sweet-ann [11.9K]

Answer:

The answer is Option D:

<em>"The distribution of all values of the statistic resulting from all samples of size taken from the same population."</em>

<em />

Step-by-step explanation:

First, is a distribution of all values. It has to include all the possible values of the statistic with its associated probability.

Second, is a distribution of a statistic because we are talking about sample results.

Third, it has to be taken from the same population and have to have the same sample size.

3 0
3 years ago
Given the function h(x)=-x^2-5x+14 determine the average rate of change of the function over the interval -9
Juli2301 [7.4K]

Answer:

The average rate of change of the function over the interval is of 6.

Step-by-step explanation:

Average rate of change:

The average rate of change of a function h(x) over an interval [a,b] is given by:

A = \frac{h(b)-h(a)}{b-a}

In this question:

Over the interval [-9,-2], so a = -9, b = -2, b - a = -2 -(-9) = 7

The function is:

h(x) = -x^2 - 5x + 14

h(-9) = -9^2 -5(-9) + 14 = -81 + 45 + 14 = -22

h(-2) = -2^2 -5(-2) + 14 = -4 + 10 + 14 = 20

Then

A = \frac{h(-2)-h(-9)}{7} = \frac{20-(-22)}{7} = \frac{42}{7} = 6

The average rate of change of the function over the interval is of 6.

8 0
3 years ago
If a =(9,18) and b=(1,12) what is the length of ab
cupoosta [38]

Answer:

AB = 10

Step-by-step explanation:

Use the distance formula: √(12 - 18)^2 + (1 - 9)^2

√36 + 64

10

7 0
3 years ago
For A Sunday Brunch, Alisha is making a recipe that requires 8 cups of milk. She has 3 quarts of milk. Does she have enough for
vredina [299]
She has more than enough because with 8 cups you only need 2 quarts. She has 3 which gives her 12 cups.
6 0
3 years ago
F(x)=X over x^3-2x^2+5x why will this have no zeros​
Mumz [18]

If you evaluate directly this function at x=0, you'll see that you have a zero denominator.

Nevertheless, the only way for a fraction to equal zero is to have a zero numerator, i.e.

\dfrac{x}{x^3-2x^2+5x}=0\iff x=0

So, this function can't have zeroes, because the only point that would annihilate the numerator would annihilate the denominator as well.

Moreover, we have

\displaystyle \lim_{x\to 0} \dfrac{x}{x^3-2x^2+5x} = \lim_{x\to 0} \dfrac{x}{x(x^2-2x+5)} = \lim_{x\to 0} \dfrac{1}{x^2-2x+5} = \dfrac{1}{5}

So, we can't even extend with continuity this function in such a way that f(0)=0

5 0
3 years ago
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