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3 years ago

What is the y-intercept of the function f(x)=4 - 5x? -5 -4 4 5

Mathematics

2 answers:

pantera1 [17]3 years ago

8 0

Answer:

b = 4

Step-by-step explanation:

Use the slope-intercept form y = m x + b to find the y-intercept b .

vlabodo [156]3 years ago

3 0

Answer:

I believe the answer is -4

Step-by-step explanation:

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the power generated by an electrical circuit (in watts) as a function of its current C (in amperes) is modeled by P(c)= -15c(c-8

katen-ka-za [31]

Answer:

c = 4 A

Step-by-step explanation:

The given function P(c) = - 15 c (c-8) is actually quadratic function:

P(c) = - 15c² + 120c or parabola

The standard form of a quadratic function is:

y = ax² + bx + c

For which x is the maximum of the parabola we can find with this formula

x = - b/2a

in this case a = -15 and b = 120 and input variable is current c

c = - 120/(2 · (-15)) = - 120/ (-30) = 4 A

c = 4 A

God with you!!!

3 0

3 years ago

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Please help the picture is

asambeis [7]

The walls are vertical so the angle opposite X would be a right angle which is 90 degrees.

X would be 180 - 90 - 35 = 55 degrees

X and 2y - 5 are complementary angles which add together to equal 90:

2y - 5 + 55 = 90

Simplify:

2y +50 = 90

Subtract 50 from both sides:

2y = 40

Divide both sides by 2:

y = 20

7 0

3 years ago

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What is the point (4,7) after a rotation of 90 counterclockwise about the origin.

kkurt [141]

Answer:

math.way will help

Step-by-step explanation:

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3 years ago

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What is the solution to the equation 37 x = 9 x + 4 ?<br> -7<br> − 1/7<br> 1/7<br> 7

natali 33 [55]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

let's solve for x ~

$37x = 9x + 4$

$37x - 9x = 4$

$28x = 4$

$x = \dfrac{4}{28}$

$x = \dfrac{1}{7}$

5 0

2 years ago

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An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach

Alexeev081 [22]

Answer:

h(x) = -16x² + 192x + 208

784ft

6 sec

13 sec

Step-by-step explanation:

h(x) = -16x² +vx + h $_{o}$

here v represent velocity

$h_{o}$ represent initial height of launch

h(x) = -16x² + 192x + 208

here a = -16

b = 192

c = 208

x = -b/2a

= -192/2(-16)

= 6

plug this value in the equation

h(x) = -16(6)² + 192(6) + 208

= 784ft

Plug h(x)=0 in the equation

0 = -16x² + 192x + 208

divide equation by -16

x² - 12x - 13 = 0

Factors

1x * -13x = -13

1x - 13x = -12

Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

(x+1)(x-13) = 0

x = -1

x = 13

Since time can not be negative so we will reject x = -1

3 0

3 years ago