Answer:
This proof can be done by contradiction.
Let us assume that 2 - √2 is rational number.
So, by the definition of rational number, we can write it as
where a & b are any integer.
⇒ 
Since, a and b are integers 
is also rational.
and therefore √2 is rational number.
This contradicts the fact that √2 is irrational number.
Hence our assumption that 2 - √2 is rational number is false.
Therefore, 2 - √2 is irrational number.
An important rule of logs is a*log b = log b^a.
Thus, 2 (log to the base 5 of )(5x^3) = (log to the base 5 of ) (5x^3)^2, or
(log to the base 5 of ) (25x^6).
Next, (1/3) (log to the base 5 of ) (x^2+6) = (log to the base 5 of ) (x^2+6)^(1/3).
Here, the addition in the middle of the given expression indicates multiplication:
2Log5(5x^3)+1/3log5(x^2+6) = (log to the base 5 of ) { (5x^3)^2 * (x^2+6)^(1/3) }.
Here we've expressed the given log quantity as a single log.
Answer:
- 5
Step-by-step explanation:
"I am a negative integer greater than -6."
This eliminates any number that is less than -6, as well as any positive number.
0 > x > -6
"I am less than -2."
This narrows down the possible numbers to:
-5, -4, -3.
"I am not equal to -2 + (-1)"
-2 + - 1
-2 - 1
- 3
The number is not '-3'.
"I am not equal to 2 - 6."
2 - 6
- 4
The number is not -4.
Your number should be -5.
Hope this helps.
Answer:
Dan=6 days Dave=12 days
Step-by-step explanation:
1/2x + 1/x = 1/4
multiply each by 8x bc 4 * 2x = 8x
4 + 8 = 2x
12 = 2x
6 = x
