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3 years ago

When constructing parallel lines how can you be sure the lines you constructed are parallel

Mathematics

2 answers:

Andru [333]3 years ago

8 0

They are both facing the same direction.

myrzilka [38]3 years ago

4 0

They parallel lines will be going in the same direction forever

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I need help pls is only 1 question

Yanka [14]

Answer:

$T = 1300$

Step-by-step explanation:

Given

$Radius, r = 9\ in$

$Height, h = 14\ in$

See attachment

Required

Determine the total surface area, T

T is calculated using:

$T = 2\pi r(r + h)$

Substitute values for r and h

$T = 2\pi * 9(9 + 14)$

$T = 2\pi * 9(23)$

Remove bracket

$T = 2\pi * 9*23$

$T = 2\pi * 207$

Take $\pi = 3.14$

So, we have:

$T = 2 * 3.14 * 207$

$T = 1299.96$

$T = 1300$ --- approximated.

Hence, the surface area is 1300 square inch

4 0

3 years ago

Which expression is a difference of squares with a factor of 2x + 5? 4x2 + 10 4x2 – 10 4x2 + 25 4x2 – 25

Shtirlitz [24]

Answer:

4x^2 -25

Step-by-step explanation:

The other factor of the difference of squares is the "conjugate" of the given one: (2x -5). Then their product is ...

(2x +5)(2x -5) = (2x)^2 -(5)^2 = 4x^2 -25

5 0

3 years ago

Read 2 more answers

4b−3.2=3(2b−4) can you plz solve

evablogger [386]

Answer:

4b-3.2=6b-12

12-3.2=6b -4b

8.8=2b

b=8.÷2

b=4.4

3 0

3 years ago

В рулоне 32 метров ткани. Отрезали одну восьмую часть. Сколько

chubhunter [2.5K]

Answer:

28 meters

Step-by-step explanation:

The question in English is

On a 32-meter roll of fabric, it cuts an eighth of the total. How many meters of fabric are left in a roll?

step 1

we know that

To find out how many meters of fabric were cut, multiply the total meters by the fraction that was cut

$32(\frac{1}{8})=4\ m$

step 2

To find out how many meters of fabric are left, subtract the meters of fabric that were cut from the total meters of fabric

$32-4=28\ m$

6 0

3 years ago

Given the circle with the equation (x + 1)2 + y2 = 36, determine the location of each point with respect to the graph of the cir

kati45 [8]

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~
\begin{cases}
\stackrel{center}{(-1,0)}\\
\stackrel{radius}{6}
\end{cases}$

so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(1-0)^2}\implies d=\sqrt{(-1+1)^2+1^2}
\\\\\\
d=\sqrt{0+1}\implies d=1$

well, the distance from the center to A is 1, namely is "inside the circle".

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(6-0)^2}\implies d=\sqrt{(-1+1)^2+6^2}
\\\\\\
d=\sqrt{0+36}\implies d=6$

notice, the distance to B is exactly 6, and you know what that means.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})
\\\\\\
\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}
\\\\\\
d=\sqrt{25+64}\implies d=\sqrt{89}\implies d\approx 9.43398$

notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.

3 0

3 years ago

Read 2 more answers