Question

What is the median of the data shown heights of the members of me.smith class

Answer 1

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{72}}}}}$

Step-by-step explanation:

Given data : 68 , 69 , 71 , 71 , 71 , 73 , 74 , 75 , 75 , 78

N ( total number of observation ) = 10

Finding the position of median

$\boxed{ \sf{median = { (\frac{n + 1}{2} )}^{th \: item} }}$

$\dashrightarrow{ \sf{median = { (\frac{10 + 1}{2} )}^{th \: item}}}$

$\dashrightarrow{ \sf{median = {( \frac{11}{2}) }^{th \: item}} }$

$\dashrightarrow{ \sf{ median = {5.5}^{th \: item}}}$

$\sf{ {5.5}^{th} }$ item is the average of 5 th and 6 th items.

Now, Finding the median

$\dashrightarrow{ \sf{median = \frac{ {5}^{th}item + {6}^{th} item}{2} }}$

$\dashrightarrow{ \sf{ \frac{71 + 73}{2} }}$

$\dashrightarrow{ \sf{ \frac{144}{2} }}$

$\dashrightarrow{ \sf{72}}$

Hope I helped!

Best regards! :D